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gtnhenbr [62]
3 years ago
9

Work out the lengths of sides a and b. Give your answers to 1 decimal place. 8 cm 5 cm

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
3 0

Answer:

Step-by-step explanation:

a = \sqrt{8^{2} + 5^{2}} = \sqrt{64+25} = \sqrt{99} = 9.9

b = \sqrt{17^{2} - 12^{2}} = \sqrt{289-144} = \sqrt{145} = 12

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At what point do the lines y=x-4 and 2x+y=2 intersect?
earnstyle [38]

Answer:

  • (2, -2)

Step-by-step explanation:

<u>Given</u>

  • y = x - 4
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<u>Solving by substitution</u>

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2 years ago
MATH HELP PLEASE 50 POINTS:
Delicious77 [7]

Answer:

f(x)=-a(x+2)(2x-1)(x-3) where a>0.

To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.

Step-by-step explanation:

The real zeros are the result of setting each factor of the polynomial to zero. By reversing this process, we find:

  • zero -2 is factor (x+2)
  • zero 1/2 is factor (2x-1)
  • zero 3 is factor (x-3)

We write them together with an unknown leading coefficient a which is negative so -a.

f(x)=-a(x+2)(2x-1)(x-3) where a>0

The leading coefficient of a polynomial determines the direction of the graph's end behavior.

  • A positive leading coefficient has the end behavior point up when an even degree and point opposite directions when an odd degree with the left down and the right up.
  • A negative leading coefficient has the end behavior point down when an even degree and point opposite directions when an odd degree with the left up and the right down.
  • This graph has all odd multiplicity. The graph will cross through the x-axis each time at its real zeros.

To graph the the polynomial, begin in the left top of quadrant 2. Then draw downwards to the first real zero on the x-axis at -2. Cross the x-axis and then curve back up to 1/2 on the x-axis. Cross through again and curve back down to cross for the last time at 3 on the x-axis. The graph then ends going down towards the right in quadrant 4. It forms an s shape.

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3 years ago
I NEED help like ASAP PLEASEEEEE
In-s [12.5K]

Answer:

This should be 0,1

Step-by-step explanation:

I can barely see the graph bit it should be 0,1

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