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2 years ago

Solve the equation 6(n −1) + 2 = n(4 + 2) + 4.

Mathematics

1 answer:

Flura [38]2 years ago

8 0

Answer:

No solution.

Step-by-step explanation:

6(n −1) + 2 = n(4 + 2) + 4

6n - 6 + 2 = 6n + 4

-4 = 4 (inconsistency)

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Integrate 1 - x / x(x2 + 1) d x by partial fractions.

solniwko [45]

Answer:

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

Step-by-step explanation:

step 1:- by using partial fractions

$[tex]\frac{1-x}{x(x^{2}+1) } =\frac{A(x^{2}+1)+(Bx+C)(x }{x(x^{2}+1) }$ ......(1)

step 2:-

solving on both sides

$1-x=A(x^{2} +1)+(Bx+C)x......(2)$

substitute x =0 value in equation (2)

1=A(1)+0

A=1

comparing x^2 co-efficient on both sides (in equation 2)

0 = A+B

0 = 1+B

B=-1

comparing x co-efficient on both sides (in equation 2)

-1 = C

step 3:-

substitute A,B,C values in equation (1)

now

$\\\int\limits^ {} \, \frac{1-x}{x(x^{2}+1) } d x =\int\limits^ {} \frac{1}{x} d x +\int\limits^ {} \frac{-x}{x^{2}+1 } d x -\int\limits \frac{1}{x^{2}+1 } d x$

by using integration formulas

i) by using $\int\limits \frac{1}{x} d x =log x+c........(a)\\\int\limits \frac{f^{1}(x) }{f(x)} d x= log(f(x)+c\\$ .....(b)

$\int\limits tan^{-1}x dx =\frac{1}{1+x^{2} } +C$ .....(c)

step 4:-

by using above integration formulas (a,b,and c)

we get answer is

$log x-\frac{log(x^{2}+1) }{2}-tan^{-1} x$

6 0

2 years ago

There is a bag filled with 5 blue and 4 red marbles.

PtichkaEL [24]

Answer:

Step-by-step explanation:

9 in total 4 blue

4/9 x 2

8/9

5 0

2 years ago

Directions: Compare the sides and angles by filling in the blank with a < or > symbol.

eduard

Answer:

Number 21 is < number 23 is > number 22 is < and number 24 is >

Step-by-step explanation:

7 0

1 year ago

A circle has the equation (x-2)^2 +y^2 =5. What are the coordinates of the circle's center?

Elina [12.6K]

The circle with center (h, k) and radius r has equation
.. (x -h)^2 +(y -k)^2 = r^2

You have
.. h = 2
.. k = 0
.. r = √5

The center is (h, k) = (2, 0).

3 0

2 years ago

WILL GIVE BRAINLIEST

Nana76 [90]

I too also need this answer.

8 0

2 years ago