25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
9.9x + 16.1
Step-by-step explanation:
SImplify using like terms
Simplify:
- 3.2x + 7.9 + 8.2 + 6.7x
- 3.2x + 6.7x + 7.9 + 8.2
- 9.9x + 16.1
-Chetan K
ninety four means $94. 36/100 means $0.36. when you put these together you get $94.36
The sum is 829.77, and the difference is 205.44
C), cause you would subtract 5 from 53 in order to move it, and would get 6x=48. Then, you would divide by six on both sides, and the answer would be x=8, so Number C.
