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3 years ago

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Let G be the center of triangle XYZ. A dilation centered at G with a scale factor of -2/3 is applied to triangle XYZ to form tri

angle X'Y'Z'. Let A be the region of the area that is covered by both XYZ and X'Y'Z'. Find A/[XYZ] where [XYZ] is the area of triangle XYZ.

1 answer:

devlian [24]3 years ago

8 0

By dilation, A/[XYZ] = 14/27.

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barxatty [35]

The recursive rule is
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The iterative rule is
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The recursive rule is given by the formula
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The iterative rule begins with the formula
$a_n=a_1+d(n-1)$ , where a₁ is the first term and d is the common difference. Our first term is 10 and our common difference is -4:
$a_n=10+(-4)(n-1)
\\\text{Using the Distributive Property,}
\\
\\a_n=10+(-4*n)+(-4*-1)
\\
\\a_n=10-4n+4
\\
\\\text{Combining like terms,}
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\\a_n=14-4n$

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Umnica [9.8K]

This is not my work but i hope this can help you with your problem
https://answers.yahoo.com/question/index?qid=20120518194118AAhi738

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2 years ago

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pickupchik [31]

Answer:

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Step-by-step explanation:

all you need to do is the 3rd root of 64

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