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MrMuchimi
3 years ago
12

Express 34% as a fraction in simplest form. A.3/4 B.34/100 C.8/25 D.17/50

Mathematics
1 answer:
Verizon [17]3 years ago
7 0
Hey there!

if i am doing this correct it should be

17/50, let me explain!

.34 is 34/100 and both of these numbers are even, thus you can divide it by 2 which will give you 17/50

Hope This Helps!!!
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The figure shows a regular hexagonal prism.
Scrat [10]

Answer:

A.415.69cm

b.323.14

Step-by-step explanation:

The height would be 10cm

The length would be 4cm

3 0
3 years ago
All ratios that are equivalent to14 to 20
gulaghasi [49]

Answer:

7/10, 14/20, 21/30, 28/40, 35/50, 42/60, 49/70, 56/80, 63/90, 70/100, 77/110, 84/120, 91/130, 98/140, 105/150, 112/160, 119/170, 126/180, 133/190, 140/200,

Step-by-step explanation:

8 0
3 years ago
A Shcool Cafeteria makes cheese sauce for macaroni using 15 cups of Swiss Cheese and 17 cups of cheddar cheese. perry tries to m
ale4655 [162]
I have a question for you does the school cafeteria make it or do the ladies????
5 0
3 years ago
GIVE OUT BRAINLY 2) Kathleen is a sales associate in a jewelry store. She earns $560/wk plus an 8% commission on sales. How much
aev [14]

700<=560+0.08x

x is total sales $

the 560 is the constant weekly pay, since we're only calculating for one week.

we're adding 0.08x to account for the 8% of the total sales

solve it for x:

700-560 <= 0.08x

140 <= 0.08x

1750 <= x

or x >= 1750

meaning she needs $1750 worth of sales that week to earn atleast $700

as for C) just draw a number line with the number 1750 in the middle and the right shaded because it is 1750 or more.

5 0
4 years ago
Given: ΔPSQ, PS = SQ
horrorfan [7]
<h2>Answer:</h2>

To solve this problem we will use Heron's formula:

A=\sqrt{s(s-a)(s-b)(s-c)}

Where a, \ b \ and \ c are the side lengths of the triangle and s is the semiperimeter (half the perimeter of the triangle). We know that:

Perimeter \ P=\triangle PSQ=PS+PQ+SQ: \\ \\ \triangle PSQ=P=50 \\ \\ Semiperimeter \ s: \\ \\ s=\frac{P}{2}=25

Also:

(I) \ PS=SQ \\ \\ (II) \ SQ-PQ = 1 \\ \\ (III) \ PS+PQ+SQ=50 \\ \\ \\ (I) \ into \ (III): \\ \\ SQ+PQ+SQ=50 \\ \\ \therefore (IV) \ 2SQ+PQ=50 \\ \\ From \ (II): \\ \\ PQ=SQ-1 \\ \\ (II) \ into \ (IV): \\ \\ 2SQ+(SQ-1)=50 \\ 3SQ-1=50 \\ 3SQ=51 \\ \\ \boxed{SQ=17} \\ \\ \boxed{PS=17} \\ \\ PQ=SQ-1=17-1 \therefore \boxed{PQ=16}

Finally:

A=\sqrt{s(s-a)(s-b)(s-c)} \\ \\ A=\sqrt{s(s-PS)(s-SQ)(s-PQ)} \\ \\ A=\sqrt{s(s-17)(s-17)(s-16)} \\ \\ A=\sqrt{25(25-17)(25-17)(25-16)} \\ \\ \boxed{A=120}

7 0
3 years ago
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