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Andre45 [30]
3 years ago
13

I didn’t mean to put the 3 there, but please help!

Mathematics
1 answer:
Akimi4 [234]3 years ago
8 0

Answer:

  1. m=y2-y1 / x2-x1
  2. m= 5-2 / 9-0
  3. 3/9 =1/3
  4. y=mx+b
  5. 2=1/3(0)+b
  6. 2=b
  7. slope is 1/3
  8. y-intr is 2

Step-by-step explanation:

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KiRa [710]
Let us cross multiply.

5/9=10/x

9 x 10= 5x

90=5x

90 <u />÷ 5= 5x <span>÷ 5

18=x

So, the answer is 18. I hope this helped you, since I just learned cross multiplication last week.</span>
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The second fret is 33.641 mm from the first fret. The third fret is 31.749 mm from the second fret. How far is the third fret fr
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Step-by-step explanation:

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3 years ago
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A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
Simplifique a expressão 10ny-10x+10ny+10y
IRISSAK [1]

Responder:

10 (2ny- (x-y))

Explicación paso a paso:

Dada la expresión 10ny-10x + 10ny + 10y, para simplificar la expresión, se deben seguir los siguientes pasos;

Paso 1; Separa la expresión en términos similares

= 10ny-10x + 10ny + 10y

= (10ny + 10ny) - (10x + 10y)

Paso 2: Factoriza los valores comunes en ambos paréntesis

10ny (1 + 1) - 10 (x-y)

= 10ny (2) - 10 (x-y)

= 20ny - 10 (x-y)

Factoriza nuestro valor común en ambos términos:

= 10 (2ny- (x-y))

3 0
3 years ago
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