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Burka [1]
3 years ago
11

Answer to 4x+9=6x+31x+11

Mathematics
2 answers:
dybincka [34]3 years ago
4 0

Answer:

393

Step-by-step explanation:

my best sum is 393 but this equation is impossible.

Veseljchak [2.6K]3 years ago
4 0

Answer:

4x+9=6x+31x+11

4x-6x-31x=11-9

-33x= 2

x=2/-33

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HELP PLEASE <br><br> Solve 8 ⋅ 32 + 3<br><br> A.18<br> B.75
Vladimir [108]
Are you sure that's all of the answer choices because 259 would be the answer.
3 0
3 years ago
One leg of an isosceles right triangle measures 5 inches. Rounded to the nearest tenth, what is the approximate length of the hy
-Dominant- [34]

Answer:

C

Step-by-step explanation:

This means that there is another leg of an isosceles triangle that is also 5 inches.

a^2 + b^2 = c^2

a = 5

b = 5

c = ?

c^2 = 5^2 + 5^2                 Combine

c^2 = 25 + 25

c^2 = 50                            Take the square root of both sides.

sqrt(c^2) = sqrt(50^2)

c = sqrt(5 * 5 * 2)                Take out 1 of two factors under the root sign.

c = 5 * sqrt(2)                      The 2 is left over because there is only 1 of them

sqrt(2) = 1.4142

c = 5 * 1.4142

c = 7.07 = 7.1

3 0
2 years ago
What is 92% of 1050km?
Mariulka [41]

Answer:

966

Step-by-step explanation:

<u>92</u> x 1050

100

966

3 0
3 years ago
Read 2 more answers
2c - 5 &lt; -21 - 2c pls
Mars2501 [29]

2c - 5 < -21 - 2c     |add 5 to both sides

2c < -16 - 2c      |add 2c to both sides

4c < -16      |divide both sides by 4

c < -4

4 0
3 years ago
Can someone explain this to me please
IrinaVladis [17]

Answer:

c. 36·x

Step-by-step explanation:

Part A

The details of the circle are;

The area of the circle, A = 12·π cm²

The diameter of the circle, d = \overline {AB}

Given that \overline {AB} is the diameter of the circle, we have;

The length of the arc AB = Half the the length of the circumference of the circle

Therefore, we have;

A = 12·π = π·d²/4 = π·\overline {AB}²/4

Therefore;

12 = \overline {AB}²/4

4 × 12 = \overline {AB}²

\overline {AB}² = 48

\overline {AB} = √48 = 4·√3

\overline {AB} = 4·√3

The circumference of the circle, C = π·d = π·\overline {AB}

Arc AB = Half the the length of the circumference of the circle = C/2

Arc AB = C/2 = π·\overline {AB}/2

\overline {AB} = 4·√3

∴ C/2 = π·4·√3/2 = 2·√3·π

The length of arc AB = 2·√3·π cm

Part B

The given parameters are;

The length of \overline {OF} = The length of \overline {FB}

Angle D = angle B

The radius of the circle = 6·x

The measure of arc EF = 60°

The required information = The perimeter of triangle DOB

We have;

Given that the base angles of the triangles DOB are equal, we have that ΔDOB is an isosceles triangle, therefore;

The length of \overline {OD} = The length of \overline {OB}

The length of \overline {OB} = \overline {OF} + \overline {FB} = \overline {OF} + \overline {OF} = 2 × \overline {OF}

∴ The length of \overline {OD} = 2 × \overline {OF} = The length of \overline {OB}

Given that arc EF = 60°, and the point 'O' is the center of the circle, we have;

∠EOF = The measure of arc EF = 60° = ∠DOB

Therefore, in ΔDOB, we have;

∠D + ∠B = 180° - ∠DOB = 180° - 60° = 120°

∵ ∠D = ∠B, we have;

∠D + ∠B = ∠D + ∠D = 2 × ∠D = 120°

∠D = ∠B = 120°/2 = 60°

All three interior angles of ΔDOB = 60°

∴ ΔDOB is an equilateral triangle and all sides of ΔDOB are equal

Therefore;

The length of \overline {OD} = The length of \overline {OB} = The length of \overline {DB}  = 2 × \overline {OF}

The perimeter of ΔDOB = The length of \overline {OD} + The length of \overline {OB} + The length of \overline {DB} = 2 × \overline {OF} + 2 × \overline {OF} + 2 × \overline {OF} = 6 × \overline {OF}

∴ The perimeter of ΔDOB = 6 × \overline {OF}

The radius of the circle = \overline {OF} = 6·x

∴ The perimeter of ΔDOB = 6 × 6·x = 36·x

3 0
3 years ago
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