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3 years ago

How to split the numbers to add

Mathematics

2 answers:

iris [78.8K]3 years ago

8 0

This sheet presumes making number into 10 helps make adding easier

2. 8 + 5 =

10 + 3 = 13 we get 3 by taking 2 from 5 and giving it to the 8 to get 10

3. 8 + 6 =

10 + 4 = 14 take 2 from 6 to give to 8 to make 10

I suspect the purpose of this is to promote mental math

larisa86 [58]3 years ago

8 0

Answer:

I'm going to explain this by doing number 2.

Step-by-step explanation:

Okay, so 8 is 2 away from 10. So we subtract 2 from 5, leaving 3. We add the 2 to the 8, making 10. Now, we add the other 3. 10+3=13. 8+5=13.

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MAJOR HELP!

ladessa [460]

Answer: Option A

$\theta=tan^{-1}(\frac{8}{6})$

Step-by-step explanation:

We can model the situation by means of a right triangle.

Where the angle $\theta$ is the angle that you make with the top of the TV.

Then the horizontal distance of 6 feet is the adjacent side and the vertical distance of 8 feet is the opposite side to the angle the.

By definition of the $tan(\theta)$ function we know that:

$tan(\theta)=\frac{opposite}{adjacent}$

Therefore:

$tan^{-1}(\frac{8}{6})=\theta$

$\theta=tan^{-1}(\frac{8}{6})$

6 0

3 years ago

19/92 written as a percentage

Solnce55 [7]

Answer:

20.65%

Step-by-step explanation:

$\frac{19}{92} \\ \\ = \frac{19 \times 100}{92} \% \\ \\ = \frac{1900}{92} \% \\ \\ = 20.6521739 \%\\ \\ = 20.65\%$

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3 years ago

Plz solve this problem of trigonometry<br>i am an aakashian

makkiz [27]

Step-by-step explanation:

$\bf L.H.S = \tt \dfrac{sec\: \theta + tan \: \theta - 1}{tan \: \theta - sec \: \theta + 1} \\ \\$

$: \implies \tt \dfrac{\frac{1}{cos \: \theta} + \frac{sin \: \theta}{cos \: \theta} - 1}{ \frac{sin \: \theta}{cos \: \theta} - \frac{1}{cos \: \theta} + 1 } \: = \dfrac{1 + sin \: \theta - cos \: \theta}{sin \: \theta + cos \: \theta} \\ \\$

$: \implies \tt\dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta + (cos \: \theta - 1)} \: \times \: \dfrac{ sin \: \theta - (cos \: \theta - 1)}{sin \: \theta - (cos \: \theta - 1)} \\ \\$

$: \implies \tt\dfrac{ sin^{2} \: \theta + cos^{2} \: \theta + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: (cos \: \theta - 1)}{sin^{2} \: \theta - (cos \: \theta - 1)^{2} } \\ \\$

$: \implies \tt\dfrac{1 + 1 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - 1 + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 - 2 \: cos \: \theta - 2 \: sin \: \theta \: cos \: \theta + 2 \: sin \: \theta}{sin^{2} \: \theta + cos^{2} \: \theta - sin^{2} \: \theta - cos^{2} \: \theta + 2 \: cos \: \theta } \\ \\$

$: \implies \tt\dfrac{2 (1 - \: cos \: \theta )- 2 \: sin \: \theta (1 - \: cos \: \theta)}{ 2 \: cos \: \theta - 2 \: cos^{2} \: \theta} \\ \\$

$: \implies \tt\dfrac{(2 + 2 \: sin \: \theta) \: \cancel{(1 - cos\: \theta)}}{2 \: cos \: \theta \: \cancel{(1 - cos \: \theta)}} \: = \: \dfrac{1 + sin \: \theta}{cos \: \theta} \\ \\$