3 years ago

15(20−10x)−8x>−6x−16 A. x<1 B.x>1 C x<5 Dx>5

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

I think ur problem is missing something bc I got this

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Solve 2x^2 +16x+50=0

musickatia [10]

$2x^2 +16x+50=0\ \ \ \ \ |:2\\\\x^2+8x+25=0\\\\x^2+2\cdot x\cdot4+25=0\ \ \ \ |+4^2\\\\\underbrace{x^2+2\cdot x\cdot4+4^2}_{(a+b)^2=a^2+2ab+b^2}+25=4^2\ \ \ \ \ |-25\\\\(x+4)^2=16-25\\\\(x+4)^2=-9 < 0-NO\ REAL\ SOLUTION$

$COMPLEX\ SOLUTIONS\\\\(x+4)^2=-9\to x+4=\pm\sqrt{-9}\\\\x+4=-3i\ \vee\ x+4=3i\ \ \ \ |-4\\\\x=-4-3i\ \vee\ x=-4+3i$

5 0

3 years ago

Help with this question please and thanks in advance

SashulF [63]

Answer: x=39

3x-15=2x+24
-2x -2x
1x-15=24
+15 +15
x=39

Explanation: Non-consecutive angles are congruent. Set the two angles equal to each other and solve for x. You should get x=39.

3 0

3 years ago

Rearrange g = t - 7g to make g the subject

muminat

I switched both sides of the equation in the very beginning so it would be easier to solve.