All categories

3 years ago

15(20−10x)−8x>−6x−16 A. x<1 B.x>1 C x<5 Dx>5

Mathematics

1 answer:

Mademuasel [1]3 years ago

6 0

I think ur problem is missing something bc I got this

You might be interested in

Please please help so I can finish this

Rom4ik [11]

$RS = \sqrt{(b-0)^{2}+(c-a)^{2}}$ and RS is simplified to $RS = \sqrt{a^{2}+b^{2}+c^{2}-2ac}$

<u>Step-by-step explanation:</u>

We know that , Distance between any two points $(x_1 , y_1)$ and $(x_2, y_2)$ is given by formula :

$Distance = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}$

In this question , we have $R(0,a)$ and $S(b,c)$ .

We need to simplify RS which is given by:

$Distance = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}$

⇒ $Distance = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}$

⇒ $RS = \sqrt{(x_1-x_2)^{2}+(y_1-y_2)^{2}}$

⇒ $RS = \sqrt{(0-b)^{2}+(a-c)^{2}}$

⇒ $RS = \sqrt{(b-0)^{2}+(c-a)^{2}}$

We know that , $(a-b)^{2} = a^{2}+b^{2}-2ab$

⇒ $RS = \sqrt{b^{2}+c^{2}+a^{2}-2ac}$

⇒ $RS = \sqrt{a^{2}+b^{2}+c^{2}-2ac}$

∴ $RS = \sqrt{(b-0)^{2}+(c-a)^{2}}$ and RS is simplified to $RS = \sqrt{a^{2}+b^{2}+c^{2}-2ac}$ .

5 0

3 years ago

Pls help me

aivan3 [116]

The and answer is going to be 3 because when you multiply 5 and 3 you get 15

3 0

2 years ago

I need help!! PLEASE PLEASEE HELP ME

zheka24 [161]

The second choice! I hope my math is right!

7 0

3 years ago

Help please quick! show work please.<br> Use the area to find the value of x:

saveliy_v [14]

Answer:

Step 1:divide

276/12=23

Step 2:

answer it!

Step-by-step explanation:

Your answer is 23. Divide the sf by the ft then you get x.

5 0

2 years ago

Read 2 more answers

When one patient with a common cold takes a medicine and the other patient does not take any medicine the person who takes medic

Kobotan [32]

What options can you choose from? I guess it would be something like the medicine works or the medicine is not a placebo

4 0

3 years ago

Read 2 more answers