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3 years ago

Marcos ran 5 2/4 miles on sat and 3 3/4 miles on monday,how much father did he run on sat

Mathematics

1 answer:

N76 [4]3 years ago

8 0

is this farther?if it is yes Answer is

5 2/4-3 3/4=22/4 - 15/4=7/4 miles farther

You might be interested in

6 squared divided by 2(3) plus 4 =

Norma-Jean [14]

6²/2(3) +4

6²=36
2(3)=6
So now we have
36/6 + 4 which is 6 + 4 which is 10.

8 0

3 years ago

Determine whether LINE AB and LINE CD are parallel, perpendicular, or neither. A(−1, −4) , B(2, 11) , C(1, 1) , D(4, 10) ( write

Luba_88 [7]

Step-by-step explanation:

Hey there!

The points of line AB are; (-1,-4) and (2,11).

Note:

Use double point formula and simplify it to get two eqaution.
Use condition of parallel lines, perpendicular lines to know whether the lines are parallel or perpendicular or nothing.

~ Use double point formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1} (x - x1)$

~ Keep all values.

$(y + 4) = \frac{11 + 4}{2 + 1} (x + 1)$

~ Simplify it.

$y + 4 = \frac{15}{3} (x + 1)$

$y + 4 = 5x + 5$

$5x - y + 1 = 0$

Therefore this is the equation of line AB.

Now, Finding the equation of line CD.

Given;

The points of line CD are; (1,1) and (4,10).

~ Using formula.

$(y - y1) = \frac{y2 - y1}{x2 - x1}(x - x1)$

~ Keep all values.

$(y - 1) = \frac{10 - 1}{4 - 1} (x - 1)$

~ Simplify it.

$y - 1 = 3 x - 3$

$3x - y - 2 = 0$

Therefore, 3x - y- 2 = 0 is the eqaution of line CD.

Use condition of parallel lines.

m1= m2

Slope of equation (i)

$m1 = \frac{ - coeff. \: of \: x}{coeff \: of \: y}$

$m1 = \frac{ - 5}{ - 1}$

Therefore, m1 = 5

Slope of second equation.

$m2 = \frac{ - coeff \: .of \: x}{coeff \: .of \: y}$

$m2 = \frac{ - 3}{ - 1}$

Therefore, m2 = 3.

Now, m1≠m2.

So, the lies are not parallel.

Check for perpendicular.

m1*m2= -1

3*5≠-1.

Therefore, they aren't perpendicular too.

So, they are neither.

Hope it helps...

6 0

3 years ago

A restaurant has 75% of its tables being used. Which ratio compares the used tables with all the tables in the restaurant?

Bogdan [553]

75%=75/100=75:100=3/4

4-3=1

1/4=tables not used.

1/4=25/100=25:100

So....25:75 = not used tables : used tables

Hoped I helped!

5 0

3 years ago

Read 2 more answers

"Rather than walk all the way

Olenka [21]

Answer:

5.8com shorter

Step-by-step explanation:

I used the pythagoremy theorem to find the missing side length.

$a^{2} +b^{2} = c^{2}\\5^{2} +3^{2} = c^{2}\\25+9= c^{2}\\34=c^{2} \\\sqrt{34} = {c}^{2}\\5.8cm$

5 0

3 years ago

a. Is it possible for a shape to have both reflectional and rotational symmetry? If so, provide an example with a line of symmet

AnnZ [28]

Yes. For example, the shape I will use is the circle.

No matter how you rotate the circle, it will always look the same. If you reflect the circle over any drawen line in which it passes through the middle, the two halves created would be congruent.

~Rise Above the Ordinary, Senpai

7 0

3 years ago