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Anastaziya [24]
3 years ago
9

Help me with this pls

Mathematics
2 answers:
zysi [14]3 years ago
8 0

ur smart u got dis fam

Step-by-step explanation:

ur talented and u r the only u, u have always been making it through since grade 1

Lostsunrise [7]3 years ago
7 0
75+15x would be the answer i’m pretty sure
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Please help me with my math homework
Dafna11 [192]

Hi there!

\large\boxed{UV = 13}

Since U and V are midpoints of the legs, then UV is the average of both WX and ZY.

Therefore:

(ZY + WX)/2 = UV

Substitute in the given expressions:

[(6x + 5) + (x + 7)]/2 = 8x - 3

Simplify by combining like terms:

(7x + 12)/2 = 8x - 3

Multiply both sides by 2:

7x + 12 = 16x - 6

Subtract 7x from both sides and add 6 to both sides:

18 = 9x

Divide both sides by 9:

18/9 = x

x = 2.

Plug in this value of x into the equation for UV:

8(2) - 3 = 16 - 3 = 13.

8 0
3 years ago
Answer please nd thank u
Maksim231197 [3]

Answer:

I can't draw number 1 and 2, but

1. 6 stacked cubes

2. 10 stacked cubes

3. f=6, e=10, v=6

4. f=5, e=12, v=8

5. f=6, e=12, v=8

5 0
2 years ago
Help pls dont give just the answer pls step by step so i can understand
Irina-Kira [14]

Answer:

y=14

Step-by-step explanation:

Since this is an isosceles triangle due to opposite sides being congruent, the base angles would also be congruent.

50 = 2x \\x=25

plug in 25 in 2x and you would get 50°

Since the sum of a triangle is 180° you could set up an equation 50+50+5y+10=180

Then, add 50+50=100+10=110

then you would then have 5y+110=180\\

subtract 110 from 180, leaving you with 70

5y=70

then divide and you would get 14

Check:

5(14)+10+50+50= 180

8 0
3 years ago
Paula walked on the treadmill for 12 minutes. The machine told her she had a total of 780 strides. What was her rate in strides
Cerrena [4.2K]

Answer:780/12=65

Step-by-step explanation:

7 0
4 years ago
craig is folding laundry for his family.in the basket,1/6 of the shirts belong to his older brother and 3/6 of the shirts belong
vladimir2022 [97]
2/3 is the fraction.
4 0
3 years ago
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