To
answer this item, we use the equation given for the calculation of the area of
the triangle.
A
= 0.5bh
Substituting
the known expressions,
A = (0.5)(3x – 6)(2x + 4)
Part
A: Use distribution method to simplify the expression for the calculation of
area.
A
= 0.5(6x^2 + 12x – 12x – 24)
A
= 0.5(6x^2 – 24)
<span> A
= 3x^2 – 12</span>
Part B: The equation for area of has a degree of two
because the highest exponent is 2.
<span>Part
C: The closure property of polynomials is always closed for multiplication.</span>
Answer: Both the equations when solved have different answers, the solutions for both the equation are given below. In the the first equation 4 (x-3)=16 , 4 is multiplied with both the terms in the bracket. Whereas, in the second equation 4x- 2 = 16 there is no variable to multiply with the LHS equation
Solution:
4 (x-3)=16
4x - 12 = 16
4x = 16 + 12
4x = 28
x = 7
4x - 3 = 16
4x = 16 + 3
4x = 19
x = 19/4
x = 4.75
Answer:
Step-by-step explanation:
Begin
If this is a rhombus then <8 = 90 degrees as do all the central angles. That's because the diagonals intersect at right angles.
<4 = 38 z formation for parallel lines.
<7 = 52 The angles are part of a right angle triangle. <7 +38 = 90
<2 = 52 z formation of parallel lines (a rhombus has ll lines).
<3 = 38 The diagonals of a rhombus bisect each other.
<5 = 38 z formation for parallel lines.
<6 = 52 The diagonals of a rhombus are angle bisectors.
<1 = 52 The diagonals of a rhombus are angle bisectors.
It's just an estimate. There's no telling how close it is.
To estimate using just the information in the table,
ASSUME that the average of all the students in each
slot is the average time of that slot.
I know that's confusing. I can't think of a better way to say it,
so here are two examples of what I mean. Look at the table:
-- 6 students said that they spent between 0 and 30 minutes.
ASSUME that those 6 students averaged 15 minutes each.
-- 21 students said that they spent between 60 and 90 minutes.
ASSUME that those 21 students averaged 75 minutes each.
So, when you add up the times for all 50 students, you'll have
(6 x 15 min) + (14 x 45 min) + (21 x 75min) + (9 x 105 min) =
When you total up all those times, divide it by 50 to estimate
the average per student.
Remember ... it's only an estimate.
If the first group had 1 student that spent 2 minutes, and
the other 5 of them spent 29 minutes, then it won't work.
But you'll never know.
