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KengaRu [80]
3 years ago
15

I WILL MARK THE. BRAINLIEST Simplify (5 1/3)^3

Mathematics
1 answer:
MrMuchimi3 years ago
3 0
Exact from is 4096/27

In decimal form is 151.703

In mixed from is 151 19/27

Hope it help u
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Please help fast will give brainliest
PolarNik [594]
It’s going to be 19/3>37>6.08171>6.012
6 0
3 years ago
How many times do you need to divide by ten to get from 5947.7 to 5.9477 ?
mixas84 [53]
Answer would be 4 times

so if u count from behind 7 to where the decimal point is it would be 4


brainliewst and thanks plz
6 0
3 years ago
Read 2 more answers
42% of jacksons halloween candy from last year was chocolate. what fraction of his candy's chocolate
vodomira [7]

Answer:

21/50

Step-by-step explanation:

Given that Jackson's sweets from last Halloween from last year was 42% chocolate, we can assume he had a total of 100 sweets.

Out of 100 sweets, 42 pieces are chocolate, so:

42/100

When simplifying this fraction into its simplest form, the most you can do is divide the numerator(top) and denominator(bottom) by 2.

Your result would be 21/50

Hope this helps!

4 0
3 years ago
Given A ={a,b,c} and B= {c,a}, which of the following is true
Sedaia [141]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Phoenix is a hub for a large airline. Suppose that on a particular day, 8000 passengers arrived in Phoenix on this airline. Phoe
Afina-wow [57]

Answer:

Step-by-step explanation:

Hello!

In a day a total of n= 8000 passangers arrived to Phoenix.

1400 of these passangers <u>final destination was Phoenix. (A)</u>

The remaining 6600 passangers were all taking c<u>onnection flights to other cities. (B)</u>

Due to several flights being late, 430 connecting passengers <u>missed their connecting flight and were delayed in Phoenix. (C)</u>

Of these 430 delayed passengers, 75 were <u>delayed overnight. (D)</u>

If there was one passenger chosend at random:

a) You have to calculate the probability of this passegners final destination to be Phoenix. Symbolically: P(A)

To calculate this probability you have to divide the number of  passengers whose final destination was Phoenix by the total number of pasengers:

P(A)= \frac{1400}{8000} = 0.175

b) The passangers whose final destination was not phoenix are those taking connection flights, the probability of this event, called B, is calculated dividing the total of connecting passengers by the total of passengers:

P(B)= \frac{6600}{8000}= 0.825

c) You need to calculate the probability of "the passenger was connecting and missed the connecting flight"

The amount of passengers that fit this situation are 430 of 8000, so the probability is calculated as:

P(C)= \frac{430}{8000} = 0.05375 ~= 0.054

d) Of all 6600 connecting passengers, only 430 missend the flight wich means that 6170 took the connecting flight, the probability of this event "E" is

P(E)= \frac{6170}{8000}= 0.771

e) The passenger either had Phoenix as a final destination or was delayed overnight, symbolically:

P(A∪D) = P(A) + P(D) - P(A∩D)

The probability of the passenger being delayed overnight is:

P(D)= \frac{75}{8000} = 0.009

The events "A" and "D" are mutually exclusive, this means that they cannot occur both at the same time, so their intersection is void, P(A∩D)= ∅

Then

P(A∪D) = P(A) + P(D) = 0.175 + 0.009= 0.184

f) If using the same data we turn this event into a binomial variable were our success will be "the passenger missed his flight and was delayed overnight" with probability p=0.009 and the sample n= 50

Let's say that the airline should be worried if more than half of the surveyed passengers were delayed overnight then:

P(X>25)= 1 - P(X ≤ 25) = 1 - 0.999999 = 0.000001

The probability of most of the surveyed passenger were delayed overnight is too low so the company should not be worried.

I hope it helps!

5 0
3 years ago
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