Given: tangent to Circle O.<br><br> If m C = 63°, then m BDR =

Mario made a table with the rules below

Lady_Fox [76]

It will be option A.
x - coordinate is 1. If we multiply 3 with 1, it will be 3. And if we multiply 3 with 3, it will be 9.
y- coordinate is 1. If we add 3 with 1, it will be 4. And adding 3 with 4, we get 7.

<u>Answer:</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0

2 years ago

It is given that quadrilateral ABCD is a kite. We know

NemiM [27]

Answer:

Kite

Perpendicular

Reflexive

HL

Step-by-step explanation: Just did it on edg 2021.

3 0

3 years ago

Read 2 more answers

Part I: Measuring Parts of a Circle

cluponka [151]

Answer:

case a) The approximate circumference of circle is $5.9\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=2.95$

case b) The approximate circumference of circle is $6\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3$

case c) The approximate circumference of circle is $6.24\ units$ and the ratio of circumference to Diameter is $\frac{C}{D}=3.12$

Step-by-step explanation:

we know that

The approximate circumference of each circle, is equal to the perimeter of each inscribed polygon

case A) the figure is an inscribed pentagon

step 1

Find the approximate circumference of circle

The perimeter of the pentagon is equal to

$P=5s$

where

$s=1.18\ units$

substitute

$P=5(1.18)=5.9\ units$

therefore

The approximate circumference of circle is $5.9\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=5.9/2=2.95$

case B) the figure is an inscribed hexagon

step 1

Find the approximate circumference of circle

The perimeter of the hexagon is equal to

$P=6s$

where

$s=1\ units$

substitute

$P=6(1)=6\ units$

therefore

The approximate circumference of circle is $6\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6/2=3$

case C) the figure is an inscribed dodecahedron

step 1

Find the approximate circumference of circle

The perimeter of the dodecahedron is equal to

$P=12s$

where

$s=0.52\ units$

substitute

$P=12(0.52)=6.24\ units$

therefore

The approximate circumference of circle is $6.24\ units$

step 2

Find the ratio of circumference to Diameter

we know that

The radius is half the diameter so

$D=2r=2(1)=2\ units$

The ratio is equal to

$\frac{C}{D}=6.24/2=3.12$

<em>Conclusion</em>

We know that

The exact value of the ratio $\frac{C}{D}$ is equal to

$\frac{\pi D}{D}=\pi$

The approximate value of the circumference will be closer to the real one when the number of sides of the inscribed polygon is greater

4 0

3 years ago

Find the lateral area and total surface area of each of the following. GEOMETRY!!! HELP PLS

AlexFokin [52]

(a) The lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.

(b) The lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.

(c) The lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.

<h3>Lateral surface area of the prism</h3>

L.S.A = Ph

where;

P is perimeter of the base
h is height of the prism

h² = 17² - 8²

h² = 225

h = 15

L.S.A = (3 x 16) x 15 = 720 sq units

<h3>Total surface area of the prism</h3>

T.S.A = PH + 2B

T.S.A = 720 + 2(16) = 752 sq units

<h3>Lateral surface area of the cone</h3>

L.S.A = πrt

where;

t is the slant height = 17

r² = 17² - 15²

r² = 64

r = 8

L.S.A = π(8)(17) = 136π sq units

<h3>Total surface area of the cone</h3>

T.S.A = πrt + πr²

T.S.A = 136π sq units + π(8)²

T.S.A = 200π sq units

<h3> Lateral surface area of the cylinder</h3>

L.S.A = 2πrh

where;

r is the radius of the cylinder = 11
h is height of the cylinder = 11

L.S.A = 2π(11 x 11) = 242π sq units

<h3>Total surface area of the cylinder</h3>

T.S.A = 2πrh + 2πr² = 2πr(r + h)

T.S.A = 2π(11)(11 + 11)

T.S.A = 484π sq units.

Thus, the lateral surface area of the prism is 720 sq units and the total surface area is 752 sq units.

the lateral surface area of the cone is 136π sq units and the total surface area is 200π sq units.
the lateral surface area of the cylinder is 242π sq units and the total surface area is 484π sq units.

Learn more about surface area here: brainly.com/question/76387

#SPJ1

3 0

2 years ago

I'm giving away all my points cause I'm done here so here yall go. <br> P.S. there will be mor e

ziro4ka [17]

its giving me 50 points just for answering this so I'm happy

4 0

2 years ago

Read 2 more answers

Given: tangent to Circle O. If m C = 63°, then m BDR =