Answer:
ρ_air = 0.15544 kg/m^3
Step-by-step explanation:
Solution:-
- The deflated ball ( no air ) initially weighs:
m1 = 0.615 kg
- The air is pumped into the ball and weight again. The new reading of the ball's weight is:
m2 = 0.624 kg
- The amount of air ( mass of air ) pumped into the ball can be determined from simple arithmetic between inflated and deflated weights of the ball.
m_air = Δm = m2 - m1
m_air = 0.624 - 0.615
m_air = 0.009 kg
- We are to assume that the inflated ball takes a shape of a perfect sphere with radius r = 0.24 m. The volume of the inflated ( air filled ) ball can be determined using the volume of sphere formula:
V_air = 4*π*r^3 / 3
V_air = 4*π*0.24^3 / 3
V_air = 0.05790 m^3
- The density of air ( ρ_air ) is the ratio of mass of air and the volume occupied by air. Expressed as follows:
ρ_air = m_air / V_air
ρ_air = 0.009 / 0.05790
Answer: ρ_air = 0.15544 kg/m^3
Answer:
ILL SEND A PIC HOLD ON ITS EASY
Step-by-step explanation:
composite numbers less than 12={1,3,4,6,8,9,10}
Answer:
43
Step-by-step explanation:
Using the remainder theorem, that is
The remainder on dividing f(x) by (x - h) is the value of f(h)
here division by (x - 3) hence evaluate f(3) for remainder
f(3) = 3² + 14(3) - 8 = 9 + 42 - 8 = 43 ← remainder
Answer:
96
Step-by-step explanation:
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