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SpyIntel [72]
3 years ago
5

Evaluate. (a−2b)3 when a=−2 and b=−12

Mathematics
2 answers:
Mariana [72]3 years ago
5 0

Step-by-step explanation:

(a−2b)

3

\{ - 2 - (2 \times - 12) \}{−2−(2×−12)}

\{ - 2 - ( - 24)\}{−2−(−24)}

\{ - 2 + 24 \}{−2+24}

2222

the required value is 22

ASHA 777 [7]3 years ago
3 0

▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪

let's evaluate :

  • (a - 2b) {}^{3}

  • \{ - 2 - (2 \times  - 12) \}

  • \{  - 2 - ( - 24)\}

  • \{ - 2 + 24 \}

  • 22

the required value is 22

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Answer:

Step-by-step explanation:

We have the following theorem, if f is a polynomial with real coefficients, we can factor it completely in factors of the degree at most 2.

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x = \frac{-b\pm \sqrt[]{b^2-4ac}}{2a}.

Note that square root, over the reals, tells us that the are only real solutions if b^2-4ac \geq 0. If that is not the case, say it's negative, the solution are complex. Then, the solutions are of the form

x = \frac{-b \pm i \sqrt[]{4ac-b^2}}{2a}. NOte that this means that if we have a complex number of the form a+bi that is a solution, then the number a-bi (who is called the complex conjugate) is also a solution.

Recall that when we have a polynomial f(x) whose a zero is the number c, then we can factor f as follows f(x) = (x-c) * p(x) where p(x) is another polynomial of lesser degree .

So far, we know that -3 and 4-i are zeros of the function f. Note that we are missing two zeros. But, since complex numbers are zeros of polynomial only by pairs (that is the number and its conjugate are zeros), then, we must have that one of the missing 2 zeros is a real number. We have 4-i as a zero, then, its complex conjugate must be also a zero, i.e 4+i is a zero.

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Can someone please help me solve for X i’m really confused and I really need help please
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Step-by-step explanation:

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almond37 [142]

Answer:

1/8 or 0.125

Step-by-step explanation:

Let x be the length of the sides of the square ABCD.

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The area of the triangle MCN is:

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Answer:

Step-by-step explanation:

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3 years ago
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