With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
<h3>What is the surface area of a truncated prism?</h3>
The <em>surface</em> area of the <em>truncated</em> prism is the sum of the areas of its six faces, which are combinations of the areas of rectangles and <em>right</em> triangles. Then, we proceed to determine the <em>surface</em> area:
A = (12 cm) · (4 cm) + 2 · (3 cm) · (4 cm) + 2 · (12 cm) · (3 cm) + 2 · 0.5 · (12 cm) · (5 cm) + (5 cm) · (4 cm) + (13 cm) · (4 cm)
A = 48 cm² + 24 cm² + 72 cm² + 60 cm² + 20 cm² + 52 cm²
A = 276 cm²
With the help of the <em>area</em> formulae of rectangles and triangles and the concept of <em>surface</em> area, the <em>surface</em> area of the composite figure is equal to 276 square centimeters.
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Step-by-step explanation:
Volume of displaced water = (10cm)(10cm)(1.6cm)
= 160 cm^3
density = mass/vol of displaced water
= 3088 grams/160 cm^3
= 19.3 g/cm^3
P.S. This is most likely a pure gold medallion.
Because the order doesn't matter on where each person sits use the combinations formula:
C = n! / (r!(n-r)!)
Where n is the total number of people and r is the number of chairs.
C = 6! / (4!(6-4)!)
C = (6*5*4*3*2*1) / ((4*3*2*1(2*1))
C = 720 / (24*2)
C = 720 / 48
C = 15
There are 15 different arrangements.
I would say its A but I'm not 100%
The answer to the question