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Dovator [93]
3 years ago
15

Consider the equation 8x + 5 = 37. Write a real-life scenario that this equation could model.

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

Dave has been introduced to a new phone service. They charge a monthly fee of $5 and each phone call made out of country is $8. How much phone calls did Dave made out of country if his bill this month was 37?

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A caterer charges a setup fee of $50, plus $20 per person. How much will the caterer charge if 35 people attend the party, and t
tiny-mole [99]

Answer:

$650

Step-by-step explanation:

35 people x $20 per person = $700

$700 + $50 set up fee = $750 dollars total

$750 - $100 coupon = $650

3 0
3 years ago
Which values are solutions to K-3 >-2? Select two options.
Ierofanga [76]

Step-by-step explanation:

k‒3>‒2=k>‒2+3

=k>1

so there is not the answer here

5 0
3 years ago
A child weighing 59 lb has a bad infection and is to be given Cefaclor.
cricket20 [7]

Answer:

Step-by-step explanation:

59:2,2=26,81

15*26,81:250=1,6086

6 0
3 years ago
The product of (3 + 2i) and a complex number is (17 + 7i).
Vesna [10]
A+bi is a complex number

(3+2i)(a+bi)=17+7i
remember
i²=-1
so
expand and solve
a is the ral part
bi is the imaginary part
ok so
if Ac+Be=dc+fe where c=c and e=e then A=d and B=f

(3+2i)(a+bi)=17+7i
expand/distribute/FOIL
3a+2ai+3bi+2bi²=17+7i
3a+2bi+2ai+2bi=17+7i
3a-2b+2ai+2bi=17+7i
real parts are 3a-2b
imaginary is 2ai+2bi
so

3a-2b=17 and
2ai+2bi=7i

we need to solve
2nd equation, divide both sides by i
2a+2b=7
multiply by -1 and add to other equation

3a+2b=17
<u>-2a-2b=-7 +</u>
1a+0b=10
a=10

subsitue
2a+2b=7
2(10)+2b=7
20+2b=7
2b=-13
b=-13/2


the complex number is
10-(13/2)i or
10-6.5i
8 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! I AM SO DUMB OMG
RUDIKE [14]

Answer:

THE CORRECT OPTION IS C) Δ RST \sim Δ UVW ; \frac{5}{6}

Step-by-step explanation:

i) ∠ WUV = ∠ TRS      ( same angle = 32 )

ii) \frac{TR}{UW}  = \frac{RS}{VU}  = \frac{15}{18} = \frac{10}{12} = \frac{5}{6} ;

Hence it is proved that

Δ RST \sim Δ UVW

3 0
3 years ago
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