Find the surface area of the triangular prism (above) using its net (below)

You are doing marketing research to find out the purchasing potential of students in the community. Based on the latest census,

Angelina_Jolie [31]

Number of students = 9860
Total Population = 62,400

Percentage of students in the population can be calculated by:

(Number of students/Total population) x 100%

Using the values, we get:

Percentage of students = (9860/62400) x 100% = 15.80%

Thus, students constitute 15.80% of the entire population

6 0

3 years ago

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Nate is exponentially gaining Twitter followers! His current amount of followers is 146. His followers are increasing at a 24% r

tia_tia [17]

Answer:

(a) Growth

$(b)\ y = 146(1.24)^x$

Step-by-step explanation:

Given

$a= 146$ -- current

$r = 24\%$ --- rate

Solving (a): Growth or decay

The question says his followers increases each day by 24%.

Increment means growth.

Hence, it is a growth problem

Solving (b): Equation to represent the scenario.

Since the rate represents growth, the equation is:

$y = a(1 + r)^x$

Substitute: $a= 146$ and $r = 24\%$

$y = 146 * (1 + 24\%)^x$

$y = 146 * (1 + 0.24)^x$

$y = 146 * (1.24)^x$

$y = 146(1.24)^x$

5 0

3 years ago

Divide: 27÷77,868 Help

Contact [7]

Answer:

this is the answer unless you did it backwards

Step-by-step explanation:

3.467406380027739e-4

8 0

3 years ago

Milo is a running back on his middle school football team. On his first running play he netted -8 yards, and on his second runni

lidiya [134]

To find average, add up the values given and then divide that number by the amount of values that you added to make the larger number.
For example:
If he ran -8 yards first and -6 yards second and they are asking you to find the average, add -8 and -6. You get -14. If you then divide by 2 because you added 2 numbers together, you end up with -7.

Hope this helps!

6 0

3 years ago

The amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and standard deviation 13 mL. Supp

andreyandreev [35.5K]

Answer:

(a) X ~ N( $\mu=63, \sigma^{2} = 13^{2}$ ).

$\bar X$ ~ N( $\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}$ ).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

Step-by-step explanation:

We are given that the amount of syrup that people put on their pancakes is normally distributed with mean 63 mL and a standard deviation of 13 mL.

Suppose that 43 randomly selected people are observed pouring syrup on their pancakes.

(a) Let X = amount of syrup that people put on their pancakes

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = mean amount of syrup = 63 mL

$\sigma$ = standard deviation = 13 mL

So, the distribution of X ~ N( $\mu=63, \sigma^{2} = 13^{2}$ ).

Let $\bar X$ = sample mean amount of syrup that people put on their pancakes

The z-score probability distribution for the sample mean is given by;

Z = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\mu$ = mean amount of syrup = 63 mL

$\sigma$ = standard deviation = 13 mL

n = sample of people = 43

So, the distribution of $\bar X$ ~ N( $\mu=63,s^{2} = (\frac{13}{\sqrt{43} } )^{2}$ ).

(b) If a single randomly selected individual is observed, the probability that this person consumes is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < X < 62.8 mL)

P(61.4 mL < X < 62.8 mL) = P(X < 62.8 mL) - P(X $\leq$ 61.4 mL)

P(X < 62.8 mL) = P( $\frac{X-\mu}{\sigma}$ < $\frac{62.8-63}{13}$ ) = P(Z < -0.02) = 1 - P(Z $\leq$ 0.02)

= 1 - 0.50798 = 0.49202

P(X $\leq$ 61.4 mL) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{61.4-63}{13}$ ) = P(Z $\leq$ -0.12) = 1 - P(Z < 0.12)

= 1 - 0.54776 = 0.45224

Therefore, P(61.4 mL < X < 62.8 mL) = 0.49202 - 0.45224 = 0.0398.

(c) For the group of 43 pancake eaters, the probability that the average amount of syrup is between 61.4 mL and 62.8 mL is given by = P(61.4 mL < $\bar X$ < 62.8 mL)

P(61.4 mL < $\bar X$ < 62.8 mL) = P( $\bar X$ < 62.8 mL) - P( $\bar X$ $\leq$ 61.4 mL)

P( $\bar X$ < 62.8 mL) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{62.8-63}{\frac{13}{\sqrt{43} } }$ ) = P(Z < -0.10) = 1 - P(Z $\leq$ 0.10)

= 1 - 0.53983 = 0.46017

P( $\bar X$ $\leq$ 61.4 mL) = P( $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{61.4-63}{\frac{13}{\sqrt{43} } }$ ) = P(Z $\leq$ -0.81) = 1 - P(Z < 0.81)

= 1 - 0.79103 = 0.20897

Therefore, P(61.4 mL < X < 62.8 mL) = 0.46017 - 0.20897 = 0.2512.

(d) Yes, for part (d), the assumption that the distribution is normally distributed necessary.

4 0

3 years ago