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almond37 [142]
2 years ago
7

What is the domain of f(x)=(1/4)^x?

Mathematics
1 answer:
atroni [7]2 years ago
3 0

\huge \bf༆ Answer ༄

The domain of given function is <u>All real numbers</u>

\sf \: f(x) = { \bigg( \dfrac{1}{4}  \bigg) }^{x}

For each value of x the function is defined.

Example -

  • For x = 1

The value is \sf\frac{1}{4}

  • For x = -1

The value is 4

꧁  \:  \large \frak{Eternal \:  Being } \: ꧂

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Please Help me !!Q 1,2,3
Virty [35]
The area of a parallelogram is the product of the length of the base and the height measured perpendicular to the base.

1i) (20 cm)*(12 cm) = 240 cm^2

2ii) (7 cm)*(7.5 cm) = 52.5 cm^2

3iii) 27 cm^2 = (6 cm)*h
.. h = (27 cm^2)/(6 cm) = 4.5 cm
4 0
3 years ago
A person can see the top of a building at an angle of 65°. The person is standing 50 ft away from
zhannawk [14.2K]

9514 1404 393

Answer:

  (b)  112.2 ft

Step-by-step explanation:

The relevant trig relation is ...

  Tan = Opposite/Adjacent

For the given geometry, this becomes ...

  tan(65°) = (height above eye level)/(50 ft)

Then we have ...

  (height above eye level) = (50 ft)tan(65°) = 107.2 ft

Adding the height of eye level will give us the height of the building.

  building height = (eye level height) + (height above eye level)

  building height = (5 ft) + (107.2 ft)

  building height = 112.2 ft

6 0
2 years ago
1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules
hoa [83]
<span>1. How much heat is absorbed by a 50g iron skillet when its temperature rises from 10oC to 124oC? Joules

Formula: Heat = mass * specific heat * ΔT

Data:
mass = 50 g = 0.050 kg
specific heat of iron = 450 J/ kg °C
ΔT = 124°C - 10°C ¿ 114 °C

=> heat = 0.050kg * 450 J / kg°C * 114°C ≈ 2.6 J

2. If a refrigerator is a heat pump that follows the first law of thermodynamics, how much heat was removed from food inside of the refrigerator if it released 492J of energy to the room? Joules

The firs law of thermodynamics is conservation of energy => energy removed from inside of the refrigerator = energy released to the room

=> Answer = 492 J

3. How much heat is needed to raise the temperature of 45g of water by 63oC? Joules

Formula: heat = mass * specific heat * ΔT

specific heat of water = 4186 J / Kg °C

heat = 0.045 kg * 4186 J/kg °C * 63°C = 11,867.31 J
</span>
7 0
3 years ago
Don’t understand please help asap
IceJOKER [234]

First you have to solve both inequalities,

3x-1>8

3x>9

x>3

and the other one

2x≤4

x≤2

then you graph each one on the number line

the graph says or, so the solution can satisfy either equation

the solution would be all real numbers except three

the way to write it is x≠3

3 0
3 years ago
Given the system of equations, what is the solution?<br><br> 2x + y = 7<br> 2x - 3y = -1
eduard

Answer: Point Form - (5/2, 2) Equation Form - 5/2, y = 2

Step-by-step explanation:

5 0
2 years ago
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