Answer:
Tony can buy three games with his savings over two months and Alice can buy six concert tickets.
Step-by-step explanation:
Over two months, Tony has watched a total of 53.6 hours of television (35.4 + 18.2). If he save $2.50 for each hour, we can multiply his total hours by the amount per hour, or 53.6 x 2.50 = $134.00. Since each game that Tony wants to buy costs $35.75, we need to divide his total savings by the cost of each game, or 134/35.75 = 3.75. Since Tony can't buy a portion of the game, the most amount of games he can buy is 3. Alice watched a total of 48.4 hours of television (21.8 + 26.6). If she also saves $2.50 per hour, then her total savings is 2.50 x 48.4 = $121.00. Since her concert tickets are $17.50 a piece, we divide her total savings: 121/17.50 = 6.9. Alice can also not buy a partial ticket, so the total amount she can buy is 6.
Answer: 



Step-by-step explanation:
From the given figure it can be seen that
Total number on cube= n(S)=6
Intersection of A and B = n(A ∩ B)= 2
Therefore,

Also, The number of elements in A = 2
Therefore,

Similarly, The number of elements in B= 6
Therefore,

The formula to find the conditional probability is given by :-

Convert all the improper fractions into mixed numbers, then simplify. Then, you do the operations.
Answer:
F. 2 1/9
Step-by-step explanation:
Step 1: Substitute q

When you plug in <em>n</em> = 1, 2, 3:
n(1) = 3
n(2) = 2.11111
n(3) = 2.3333
So our answer is F.
Answer:
yes
Step-by-step explanation: