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Keith_Richards [23]
1 year ago
9

Simplify 5x^2+43x-18=0

Mathematics
1 answer:
GalinKa [24]1 year ago
8 0

Answer:

-9, 2/5

Step-by-step explanation:

5x^2 +43x-18=0 \\ \\ (5x-2)(x+9)=0 \\ \\ x=-9, \frac{2}{5}

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What is the volume of a right circular cylinder with a base diameter of 18yd. And a height of 3yd.
saveliy_v [14]

Answer:

Volume=254 to the nearest cubic yard.

Step-by-step explanation:

The volume of a right circular cylinder can be calculated using the formula;

Volume=\pi r^2h.

The diameter of the base is given to us. We divide it into two to obtain the radius.

r=\frac{18}{2}=9yd and also the height of the cylinder is h=3yd.

We substitute these values into the formula to obtain;

Volume=9^2\times 3\pi yd^3

Volume=243\pi yd^3

Volume=763.4yd^3

8 0
3 years ago
What is the equation in point-slope form of the line passes through the point (-8,5) and has a slope of 2?
kkurt [141]

Answer:

Do not know

Step-by-step explanation:

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3 years ago
if alpha beta are the roots of the equation 2 x square - 6 x + 5 is equal to 0 find the equation whose roots are alpha / beta an
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Answer:

Step-by-step explanation:

6 0
3 years ago
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A float in the tournament of roses parade may use as many flowers as a florist sells in 6 years. If f is the number of flowers a
BigorU [14]

6f = x

x stands for how many flowers the parade can use

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3 years ago
Scientist can determine the age of ancient objects by a method called radiocarbon dating. The bombardment of the upper atmospher
Artemon [7]

Answer: 2500 years

Step-by-step explanation:

I'm not quite sure if I'm doing this right myself but I'll give it a shot.

We use this formula to find half-life but we can just plug in the numbers we know to find <em>t</em>.

A(t)=A_{0}(1/2)^t^/^h

We know half-life is 5730 years and that the parchment has retained 74% of its Carbon-14. For A_{0 let's just assume that there are 100 original  atoms of Carbon-14 and for A(t) let's assume there are 74 Carbon-14 atoms AFTER the amount of time has passed. That way, 74% of the C-14 still remains as 74/100 is 74%. Not quite sure how to explain it but I hope you get it. <em>h</em> is the last variable we need to know and it's just the half-life, which has been given to us already, 5730 years, so now we have this.

74=100(1/2)^t^/^5^7^3^0

Now, solve. First, divide by 100.

0.74=(0.5)^t^/^5^7^3^0

Take the log of everything

log(0.74)=\frac{t}{5730} log(0.5)

Divide the entire equation by log (0.5) and multiply the entire equation by 5730 to isolate the <em>t</em> and get

5730\frac{log(0.74)}{log(0.5)} =t

Use your calculator to solve that giant mess for <em>t </em>and you'll get that <em>t</em> is roughly 2489.128182 years. Round that to the nearest hundred years, and you'll find the hopefully correct answer is 2500 years.

Really hope that all the equations that I wrote came out good and that that's right, this is definitely the longest answer I've ever written.

5 0
3 years ago
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