Answer: $55.64
Step-by-step explanation: 7% of 52 dollars is $3.64 add that to $52 and you get 55.64
1/3s+14=26
minus 14 both sides
1/3s=12
multiply both sides by 3/1
s=36
Answer:
-20, -12, -8, -1, 1, 5, 10
Step-by-step explanation:
Answer:
(a) ![E(X) = 0.383](https://tex.z-dn.net/?f=E%28X%29%20%3D%20%200.383)
The expected number in the sample that treats hazardous waste on-site is 0.383.
(b) ![P(x = 4) = 0.000169](https://tex.z-dn.net/?f=P%28x%20%3D%204%29%20%3D%200.000169)
There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
Step-by-step explanation:
Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.
N = 209
Only eight of these facilities treated hazardous waste on-site.
r = 8
a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?
n = 10
The expected number in the sample that treats hazardous waste on-site is given by
![$ E(X) = \frac{n \times r}{N} $](https://tex.z-dn.net/?f=%24%20E%28X%29%20%3D%20%20%5Cfrac%7Bn%20%5Ctimes%20r%7D%7BN%7D%20%24)
![$ E(X) = \frac{10 \times 8}{209} $](https://tex.z-dn.net/?f=%24%20E%28X%29%20%3D%20%20%5Cfrac%7B10%20%5Ctimes%208%7D%7B209%7D%20%24)
![$ E(X) = \frac{80}{209} $](https://tex.z-dn.net/?f=%24%20E%28X%29%20%3D%20%20%5Cfrac%7B80%7D%7B209%7D%20%24)
![E(X) = 0.383](https://tex.z-dn.net/?f=E%28X%29%20%3D%20%200.383)
Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.
b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site
The probability is given by
For the given case, we have
N = 209
n = 10
r = 8
x = 4
![$ P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}} $](https://tex.z-dn.net/?f=%24%20P%28x%20%3D%204%29%20%3D%20%20%5Cfrac%7B%5Cbinom%7B8%7D%7B4%7D%20%5Cbinom%7B209%20-%208%7D%7B10%20-%204%7D%7D%7B%5Cbinom%7B209%7D%7B10%7D%7D%20%24)
![$ P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}} $](https://tex.z-dn.net/?f=%24%20P%28x%20%3D%204%29%20%3D%20%20%5Cfrac%7B%5Cbinom%7B8%7D%7B4%7D%20%5Cbinom%7B201%7D%7B6%7D%7D%7B%5Cbinom%7B209%7D%7B10%7D%7D%20%24)
![$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}](https://tex.z-dn.net/?f=%24%20P%28x%20%3D%204%29%20%3D%20%20%5Cfrac%7B70%20%5Ctimes%2084944276340%7D%7B35216131179263320%7D)
![P(x = 4) = 0.000169](https://tex.z-dn.net/?f=P%28x%20%3D%204%29%20%3D%200.000169)
Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.
The answer is 3500 meters.
1 km = 1000 meters. This means that 3.5 x 1000 = 3500