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Makovka662 [10]
3 years ago
14

Help please BRAINLEISTTTTT

Mathematics
1 answer:
lesya [120]3 years ago
7 0

Answer:

1) v 2)t 3)-5, 5.5

Step-by-step explanation:

ztydh

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This graph looks like a trigonometric function. Which trigonometric function would be best to use for this model: cosine, sine,
Trava [24]
Sine wave with amplitude 0.25
Period is 4/3
h(t) = 0.25Sin((2Pi/4/3)t) = 0.25Sin((3Pi/2)t)
5 0
3 years ago
A rectangle has an area of 221 square units. The width of the rectangle is 13 units. The length of the rectangle is 3x + 2. What
vodka [1.7K]
The length is 17 and x=5


13 times 3x+2 = 221 so solve by dividing 221 by 13= 17.
Now we know that 3x+2= 17 so 3x= 15
x=5 

8 0
3 years ago
F(x) = x². What is g(x)?<br> A.g(x)=(1/3x)^2<br> B:g(x)=1/3x^2<br> C:g(x)=1/9x^2<br> D:g(x)=3x^2
lana [24]

Answer:

B

Step-by-step explanation:

We know that 3² = 9, so for g(x) to pass through (3,3), we need to multiply x² by 1/3, giving option B.

8 0
1 year ago
The graph shows the location of point P and point R. Point R is on the y-axis and has the same y-coordinate as point P. Point Q
Mumz [18]

Answer:

n = 5

Step-by-step explanation:

Coordinate of P = (n,3)

R is on y-axis & the y-coordinate of P & R are equal. So coordinate of R = (3,0)

Coordinate of Q = (n,-2)

Using distance formula,

Distance between P & Q =

\sqrt{ {( n  -  n}) ^{2} +  {( 3-  ( - 2)  })^{2}   }

=  >  \sqrt{ {(3 + 2)}^{2} }  =  \sqrt{ {5}^{2} }  = 5

Distance between P & R =

\sqrt{ {(n - 0)}^{2} +  {(3 - 3)}^{2}  }

=  >  \sqrt{ {n}^{2} }  = n

But in question it is given that distance between P & Q is equal to the distance between P & R. So,

n = 5

8 0
2 years ago
Help!!! Will give brainliest to correct answer.....
zlopas [31]
I believe the answer is C.

93.53 - 21.41 = 72.12

If you simplify C, its answer becomes equivalent to the answer of the original problem:

(90 - 20) + (3 - 1) + (0.5 - 0.4) + (0.03 - 0.01)

70 + 2 + 0.1 + 0.02

72.12
7 0
3 years ago
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