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scZoUnD [109]
3 years ago
10

Kim persuaded seven-eighths of the people in the audience to vote for him in the city council election. What percent of the peop

le in the audience did Kim persuade to vote for him?
Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0
Divide 7 by 8 the multiply by 100. 87.5%
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Penelope has $1,459.75 in her bank account. To pay her bills, she writes 4 checks for $200.25, $359.45, $125, and $299.35. Then
sammy [17]
1,459.75 - 200.25 - 359.45 - 125.00 - 299.35 = 475.70

475.70 + 375.00 = 850.70

Her account balance after the bills and deposit is $850.70
8 0
3 years ago
Read 2 more answers
PLEASE HELP PLEASE HELP PLEASE
fiasKO [112]

Answer:

384 cm

Step-by-step explanation:

Perimeter is the sum of all external sides. (do not mix this up with area. Perimeter is the easy one) :)

There are 4 external sides.

Top = bottom = 132 cm

Left = Right = 60 cm

Add all 4 sides:

2(132) + 2(60)

264 + 120 = 384 cm

4 0
2 years ago
What do you get when you combine the following numbers? -4-4-4-4
sladkih [1.3K]

Answer:

-16

Step-by-step explanation:

you just add all of them together

4 0
2 years ago
In an Algebra II class with 135 students, the final exam scores have a mean of 72.3 and standard deviation 6.5. The exams on the
gregori [183]
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5

Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students

Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students

Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68

Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
4 0
3 years ago
What is 0.01% written as a decimal
NikAS [45]
I am pretty confident its 1.0
5 0
3 years ago
Read 2 more answers
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