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3 years ago

Log2cos(x) How do I find the derivative of the following question

Mathematics

1 answer:

I am Lyosha [343]3 years ago

5 0

You can put it in a TI84 calculator and find the answer.

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Tom borrowed $8,000 for 4 years to make improvements on his house. If he repaid a total of $10,320, what interest rate did he bo

mina [271]

The loans interest rate is 6.57305%

See photo for additional details

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2 years ago

Help me get an 80 please!

guajiro [1.7K]

Answer:

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

At Pizzazz Pizza, the total price for 5

ira [324]

Answer:

The answer to your question is $9.5

Step-by-step explanation:

Data

Large pizza = L

Medium pizza = m

Write equation for both situations

Situation 1 5L + 2m = 81.5

Situation 2 4L + 3m = 78.5

Solve the system of equation by elimination

Multiply situation 1 by -3 and situation 2 by 2

-15L - 6m = -244.5

8L + 6m = 157

-7L = -87.5

Solve for L L = -87.5/-7

L = $12.5

Substitute L in Situation 1 to find m

5(12.5) + 2m = 81.5

62.5 + 2m = 81.5

2m = 81.5 - 62.5

2m = 19

m = 19/2

m = $ 9.5

The prize of a medium pizza is $9.5

8 0

3 years ago

Find the midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9)

JulsSmile [24]

The midpoint of the line segment with endpoints at the given coordinates (-6,6) and (-3,-9) is $\left(\frac{-9}{2}, \frac{-3}{2}\right)$

Solution:

Given, two points are (-6, 6) and (-3, -9)

We have to find the midpoint of the segment formed by the given points.

The midpoint of a segment formed by $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { and }\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)$ is given by:

$\text { Mid point } \mathrm{m}=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

$\text { Here in our problem, } x_{1}=-6, y_{1}=6, x_{2}=-3 \text { and } y_{2}=-9$

Plugging in the values in formula, we get,

$\begin{array}{l}{m=\left(\frac{-6+(-3)}{2}, \frac{6+(-9)}{2}\right)=\left(\frac{-6-3}{2}, \frac{6-9}{2}\right)} \\\\ {=\left(\frac{-9}{2}, \frac{-3}{2}\right)}\end{array}$