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krok68 [10]
3 years ago
14

Choose an equation of a line through the point (-4, 1) perpendicular to y=−12x+3.

Mathematics
1 answer:
Ilia_Sergeevich [38]3 years ago
4 0

Answer:

y = \frac{1}{12}x + \frac{4}{3}

Step-by-step explanation:

slope of perpendicular line: m = \frac{1}{12}

solve for b:

1 = \frac{1}{12}(-4) + b

solve parenthesis:

1 = -\frac{1}{3}+b

add \frac{1}{3} to both sides:

b = \frac{4}{3}

final equation: y = \frac{1}{12}x + \frac{4}{3}

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so to find the equation tangent to the curve x^2+1 at the point (1,2)

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