Question

Write a function similar to keep_ints like before, but now it takes in a number n and returns a function that has one parameter cond. The returned function prints out numbers from 1 to n where calling cond on that number returns True.

Answer 1

Answer:

def make_keeper(n):

   """Returns a function which takes one parameter cond and prints

   out all integers 1..i..n where calling cond(i) returns True.

   >>> def is_even(x):

       # Even numbers have remainder 0 when divided by 2.

       return x % 2 == 0

   >>> make_keeper(5)(is_even)

   2

   4

   """

   def fun(cond):

       for i in range(1,n):

           if(cond(i)):

               print(i)

   return fun

Explanation:

• Define a function called fun that takes cond as input.
• loop from 1 to n and display the value if it meets the requirement.