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pantera1 [17]
3 years ago
11

Plz help i need to finish this asap so i can graduate

Mathematics
1 answer:
Sloan [31]3 years ago
8 0
F(x) = x^2 + 3x + 2
if g(x) is the reflection of f(x) across the x - axis then
g(x) = -f(x)
g(x) = - (x^2 + 3x + 2)
g(x) = - x^2 - 3x - 2
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A car is traveling at a rate of 99 kilometers per hour. what is the car's rate in kilometers per minute? how many kilometers wil
gayaneshka [121]

there are 60 minutes per hour

99/60 = 1.65 km per minute

1.65 x 2 = 3.3 km in 2 minutes

7 0
4 years ago
Please help differentiate this!!!!!!!!!
vlada-n [284]
\bf h=20ln(3t+2)+30\\\\
-------------------------------\\\\
\boxed{a}\\\\
\stackrel{0~years}{t=0}\qquad h=20ln[3(0)+2]+30\implies h=20ln(2)+30
\\\\\\
h\approx 43.86
\\\\\\
\boxed{b}\\\\
\stackrel{1~meter}{h=100}\qquad 100=20ln(3t+2)+30\implies 70=20ln(3t+2)
\\\\\\
\cfrac{70}{20}=ln(3t+2)\implies \stackrel{\textit{log cancellation rule}}{e^{\frac{7}{2}}=e^{ln(3t+2)}}\implies e^{\frac{7}{2}}=3t+2
\\\\\\
e^{\frac{7}{2}}-2=3t\implies \cfrac{e^{\frac{7}{2}}-2}{3}=t\implies 10.371817\approx t

\bf \boxed{c}\\\\
\cfrac{dh}{dt}=20\left(\cfrac{1}{3t+2}\cdot 3  \right)+0\implies \cfrac{dh}{dt}=20\left(\cfrac{3}{3t+2} \right)\\\\\\ \cfrac{dh}{dt}=\cfrac{60}{3t+2}
\\\\\\
\left. \cfrac{dh}{dt}  \right|_{3}\implies \cfrac{60}{3(3)+2}\implies \cfrac{60}{11}
\\\\\\
\left. \cfrac{dh}{dt}  \right|_{10}\implies \cfrac{60}{3(10)+2}\implies \cfrac{15}{8}
5 0
3 years ago
Read 2 more answers
Convert 65 degrees to Radians
tensa zangetsu [6.8K]

Answer:

1.13446401 Radains

7 0
4 years ago
Determine whether the function is odd, even, neither, or can’t be determined: g(x) = x2 + x Question options:
Anastasy [175]

I have already done this question. The correct answer is c

7 0
4 years ago
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The general solution to the second-order differential equation y′′+10y=0 is in the form y(x)=c1cosβx+c2sinβx. Find the value of
allsm [11]

Answer:β=√10 or 3.16 (rounded to 2 decimal places)

Step-by-step explanation:

To find the value of β :

  • we will differentiate the y(x) equation twice to get a second order differential equation.
  • We compare our second order differential equation with the Second order differential equation specified in the problem to get the value of β

y(x)=c1cosβx+c2sinβx

we use the derivative of a sum rule to differentiate since we have an addition sign in our equation.

Also when differentiating Cosβx and Sinβx we should note that this involves function of a function. so we will differentiate  βx in each case and multiply with the differential of c1cosx and c2sinx respectively.

lastly the differential of sinx= cosx and for cosx = -sinx.

Knowing all these we can proceed to solving the problem.

y=c1cosβx+c2sinβx

y'= β×c1×-sinβx+β×c2×cosβx  

y'=-c1βsinβx+c2βcosβx

y''=β×-c1β×cosβx + (β×c2β×-sinβx)

y''= -c1β²cosβx -c2β²sinβx

factorize -β²

y''= -β²(c1cosβx +c2sinβx)

y(x)=c1cosβx+c2sinβx

therefore y'' = -β²y

y''+β²y=0

now we compare this with the second order D.E provided in the question

y''+10y=0

this means that β²y=10y

β²=10

B=√10  or 3.16(2 d.p)

5 0
3 years ago
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