The graph that looks like this is the correct answer.
It can’t, we made a chart in my class, with parallelograms and the top and kites and trapezoids are on the same level so they can’t be the same
Ok
so the focus is on the opening side of the parabola
so for a vertex of (h,k)
opening up and down
(x-h)²=4p(y-k)
p is the distance from vertex to focus
it is also the distance from the vertex to the closes point on directix
2p=distance from focus to directix
p is positive if the focus is above the directix
ok
y=9 and (7,6)
9>6
directix is above the vertex
p is negative
find distance
from 9 to 6 is 3
3=2p
1.5=p
p is negative
and the vertex will be 1.5 above the focus and 1.5 below the directix
vertex is (7,7.5)
(x-7)²=4(-1.5)(y-7.5) is de equation
The answer is 12 a this is how to solve it:
5a+3a+14+4(a-6)+10
5a+3a+14+4a-24+10
8a+14+4a-24+10
12a+14-24+10
12a-10+10
12a
ΔABC is an obtuse triangle
∠ ABC = ∠ABD + ∠ DBC = 60° + 40° = 100°
thus ∠ ABC = 100° is an obtuse angle
hence ΔABC is an obtuse triangle