Answer:
Step-by-step explanation:
Since the number of A seats is equal to the number of non-A seats, that number is half the total, or 55000/2 = 27,500.
When the stadium is sold out, the revenue from the Section A seats is ...
$25 × 27,500 = $687,500
That means the revenue from sections B and C will be ...
$1,171,000 -687,500 = $483,500
If "b" represents the number of Section B seats, then (27,500-b) will be the number of Section C seats. The revenue equation for these seats is ...
$20×b + $15×(27500-b) = $483,500
5b = 71000 . . . . . . . . . . . simplify, subtract $412,500, divide by $
b = 14,200 . . . . . . . . . . . . divide by 5; number of section B seats
27500-b = 13,300 . . . . . .section C seats
Each section holds ...
- A: 27,500 seats
- B: 14,200 seats
- C: 13,300 seats
