We apply the concept of calculus here. You can determine the minimum or maximum in here if you take the derivative of a function and equate it to zero. The solution is as follows:

n = 20t² - 20t +120
dn/dt = 0 = 40t - 20 + 0
40t - 20 = 0
40t = 20
t = 20/40
t = 1/2 or 0.5

Therefore, the number of bacteria would be minimal at 0.5°C.

4 0

3 years ago

In a college parking lot, the number of ordinary cars is larger than the number of sport utility vehicles by 77.3%. the differen

mezya [45]

Let x be the number of ordinary cars

Let y be the number of SUV's

The difference between the number of ordinary cars and the number of suvs is 17.

So x-y=17 ----> first equation

The number of ordinary cars is larger than the number of sport utility vehicles by 77.3%.

ordinary cars = SUV + 77.3% of SUV

x = y + 0.773y

x = 1.773y

Now we solve for y

We plug in x=1.773y in first equation

1.773y - y=17

0.773y = 17

y = 21.9922

Number of SUV's = 22

6 0

4 years ago

Describe the solutions for the quadratic equation shown below:

PtichkaEL [24]

The solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

To determine the the type of roots the quadratic equation 9x² - 6x + 5 = 0, we use the quadratic formula to find the roots.

So, for a quadratic equation ax + bx + c = 0, the roots are

$x = \frac{-b +/- \sqrt{b^{2} - 4ac} }{2a}$

With a = 9, b = -6 and c = 5, the roots of our equation are

$x = \frac{-(-6) +/- \sqrt{(-6)^{2} - 4 X 9 X 5} }{2 X 9} \\x = \frac{6 +/- \sqrt{36 - 180} }{18} \\x = \frac{6 +/- \sqrt{-144} }{18} \\x = \frac{6 +/- \sqrt{-12} }{18}\\x = \frac{6}{18} +/- i\frac{12}{18} \\x = \frac{1}{3} +/- i\frac{2}{3} \\x = \frac{1 + 2i}{3} or \frac{1 - 2i}{3}$

Since the roots of the equation are (1 + 2i)/3 and (1 - 2i)/3, there are 2 complex roots.

So, the solutions for the quadratic equation 9x² - 6x + 5 = 0 are A. 2 complex roots

Learn more about quadratic equations here:

brainly.com/question/18117039

5 0

3 years ago