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IgorC [24]
2 years ago
9

BIG IDEAS MATH

Mathematics
1 answer:
miv72 [106K]2 years ago
3 0

The minimum and maximum numbers of hours you will have cruise control on are 2.75 hours and 3.75 hours, respectively

<h3>How to find the minimum and maximum numbers of hours you will have cruise control on?</h3>

The given parameters are

Distance = 195 miles

Speed = 60 miles per hour

Distance to turn the cruise control off = 30 miles within the border on either sides

The distance when you turn the cruise off is:

Distance = Current Distance ± Distance to turn the cruise control off

This gives

Distance = 195 ± 30

Expand

Distance = (195 - 30, 195 + 30)

Evaluate

Distance = (165, 225)

Recall that

Speed = 60 miles per hour

So, we have:

Time = Distance/Speed

This gives

Time = (165, 225)/60

Expand

Time = (165/60, 225/60)

Evaluate

Time = (2.75, 3.75)

Hence, the minimum and maximum numbers of hours you will have cruise control on are 2.75 hours and 3.75 hours, respectively i.e. you will travel at least 2.75  hour(s) and at most 3.75 hour(s) with cruise control on.

Read more about speed at:

brainly.com/question/4931057

#SPJ1

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Alex needs 80 cm of thread for a sewing project. The thread is on a spool with a circumference of 10 cm. How many times must Ale
Rina8888 [55]

<u>Answer-</u>

<em>Alex must Alex unwind the spool </em><em>8 times</em><em> in order to get the length of thread he needs.</em>

<u>Solution-</u>

The length of the thread needed for sewing project = 80 cm

The length of the thread unwinded with each rotation of the spool = circumference of the spool = 10 cm

So, the number of turns Alex must unwind,

=\dfrac{\text{length of thread needed}}{\text{circumference of the spool}}

=\dfrac{80}{10}\\\\=8

Therefore, he must unwind 8 times to get the length he needs.


8 0
4 years ago
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How do I solve -16 x &lt; -64
matrenka [14]
You divide both sides by -16 so you get
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3 years ago
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Suppose you toss a6 sided die 40 times, with 14 tosses landing on the 5. What percentages of the tosses would be fives?
dezoksy [38]
1/6 percent of the dice has a chance for it to land on the number 5, 
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5 0
3 years ago
la spent her whole allowance of $2.00, plus the 16¢ she had left over from last week, onbubble gum. If the pieces of gum had bee
nasty-shy [4]
Let the number of pieces of gum be g and the cost of each piece be c.
gc=2.16. Also, (g+3)(c-0.01)=2.16.
So gc=(g+3)(c-0.01)=gc-0.01g+3c-0.03.
And -0.01g+3c=0.03 and c=2.16/g. -0.01g+6.48/g=0.03.
-0.01g²+6.48=0.03g; 0.01g²+0.03g-6.48=0 which can be more conveniently written:
g²+3g-648=0=(g+27)(g-24) so g=24, the number of pieces she actually had.
CHECK The cost of the gum, c=2.16/24=9 cents.
A penny cheaper makes the gum 8 cents a piece and she could have bought 27 pieces instead of 24.
5 0
3 years ago
Make x the subject: y=x+p/x-p<br><br><br>step-by-step explanation please​
Vedmedyk [2.9K]

Answer:

x = p + yp / y - 1

Step-by-step explanation:

y = x+p / x-p

y(x-p) = x + p

y(x-p) -x = p

yx - yp - x = p

yx - x = p + yp

x(y - 1) = p + yp

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