Find the lengths of x and y.
1 answer:
See the attached figure to better understand the problem
we know that
in the triangle ABD
<span>applying the Pythagorean theorem
y</span>²=3³+4²---------> y²=25------------> y=5 units
tan alfa=4/3-----------> equation 1
in the triangle BDC
tan alfa=DC/BD----------> tan alfa=(x-3)/4------------> equation 2
<span>matching equations 1 and 2
4/3=</span>(x-3)/4---------> 4*4=3*(x-3)--------> 16=3x-9---------> 3x=25----> x=25/3 units
the answer is
x=25/3 units
y=5 units
we know that
in the triangle ABD
<span>applying the Pythagorean theorem
y</span>²=3³+4²---------> y²=25------------> y=5 units
tan alfa=4/3-----------> equation 1
in the triangle BDC
tan alfa=DC/BD----------> tan alfa=(x-3)/4------------> equation 2
<span>matching equations 1 and 2
4/3=</span>(x-3)/4---------> 4*4=3*(x-3)--------> 16=3x-9---------> 3x=25----> x=25/3 units
the answer is
x=25/3 units
y=5 units
You might be interested in
Answer:
The correct option is C.
Step-by-step explanation:
The quadratic parent function is
The translation is defined as
.... (1)
Where, k is vertical stretch, a is horizontal shift and b is vertical shift.
If |k|>1, then graph of parent function stretch vertically by factor |k| and if 0<|k|<1, then parent function compressed vertically by factor |k|. Negative k represents the reflection across x axis.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
The graph shift 1 unit right,vertically stretch by a factor of 5 , reflect over the x-axis. So, a=-1, |k|=5 and k=-5
Substitute a=-1 and k=5 in equation (1).
Therefore the correct option is C.