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3 years ago

May I know why is the answer 1/2? Any idea Thank you!

Mathematics

1 answer:

ElenaW [278]3 years ago

8 0

let's put value of t in equation.

x = 2√t

x = 2√y

x/2 = √y

(x/2)^2 = y

y = x^2 /4

now let's differentiate it with respect to x.

dy/dx = 2x/4 = x/2

differentiating again wrt to x

d^2y/dx^2 = 1/2

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mina [271]

Answer:

y-intercept = a +y^2/12 term in it.

Then for y=6, you have

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If your point is (2√3, 6), then this is

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Then the hyperbola's equation is

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3 years ago

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2 years ago

A man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast

Talja [164]

Answer:

4.41 feet per second.

Step-by-step explanation:

Please find the attachment.

We have been given that a man flies a kite at a height of 16 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. We are asked to find how fast must he let out the string when the kite is flying on 34 ft. of string.

We will use Pythagoras theorem to solve for the length of side x as:

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$x^2=34^2-16^2$

$x^2=900\\\\x=30$

Now, we will use Pythagorean theorem to relate x and y because we know that the vertical side (16) is always constant.

$x^2+16^2=y^2$

Let us find derivative of our equation with respect to time (t) using power rule and chain rule as:

$2x\cdot \frac{dx}{dt}+0=2y\cdot \frac{dy}{dt}$

We have been given that $\frac{dx}{dt}=5$ , $y=34$ and $x=30$ .

$2(30)\cdot 5=2(34)\cdot \frac{dy}{dt}$

$300=68\cdot \frac{dy}{dt}$

$\frac{dy}{dt}=\frac{300}{68}$

$\frac{dy}{dt}=4.4117647058823529$

$\frac{dy}{dt}\approx 4.41$

Therefore, the man must let out the string at a rate of 4.41 feet per second.

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4 years ago

Vikentia [17]

Answer:180

Step-by-step explanation:

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3 years ago

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