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3 years ago

Why are 1 4 9 16 and 25 called perfect squares

Mathematics

2 answers:

Leokris [45]3 years ago

5 0

Because they are squares of integer numbers.

$1=1^2\\
4=2^2\\
9=3^2\\
16=4^2\\
25=5^2$

olga nikolaevna [1]3 years ago

4 0

Perfect squares can be divided and multiplied by the same number to get the same number. For example 25/5=5. 5*5=25.
4/2=2, 2*2=4
1/1=1, 1*1=1
9/3=3, 3*3=9
16/4=4, 4*4=16.
Hence the perfect squares.

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What is 4.74 divided by 0.06 (needed by this Friday, today is Tuesday, March 5th, I also need to know what 19.44 divided by 0.54

sladkih [1.3K]

4.74/.06=79

19.44/.54=36

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3 years ago

Solve for x 7 x + 15 equals 38

Galina-37 [17]

Answer:

x = 23/7

Step-by-step explanation:

7 x + 15 equals 38

7x+15 = 38

Subtract 15 from each side

7x+15-15 = 38-15

7x = 23

Divide each side by 7

7x/7 = 23/7

x = 23/7

6 0

3 years ago

Read 2 more answers

Find the area under the curve y = 27/x3 from x = 1 to x = t. Evaluate the area under this curve for t = 10, t = 100, and t = 100

Darina [25.2K]

Answer:

Step-by-step explanation:

given is a function as

$y=\frac{27}{x^3}$

We are to find the area form x=1 to x=t

The curve from x=1 lies in the I quadratnt.

So area above x axis is to be calculated

Area = $\int\limits^t_1 {\frac{27}{x^3} } \, dx \\=\frac{-27}{2x^2} \\= \frac{-27}{2t^2}-\frac{-27}{2}\\=\frac{27}{2}(1-\frac{1}{t^2} )$

a) When t =10,

area = $\frac{27}{2} (1-\frac{1}{10^2} )\\= 13.365$

b) t=100

area = $\frac{27}{2} (1-\frac{1}{100^2} )\\= 13.49865$

c) t=10000

area = $\frac{27}{2} (1-\frac{1}{10000^2} )\\= 13.5$

6 0

3 years ago

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s2008m [1.1K]

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3 years ago

Before going to school, Eudora ran from her home to a secret laboratory at an average speed of 12 km. Since she was running late

Brrunno [24]

Answer:

Eudora spent 0.5 hours in running and 1.5 hours flying using her jet-pack.

Step-by-step explanation:

Let x represent time spent in running.

We have been given that the entire trip took 2 hours, so time spent in flying the jet-packs would be $2-x$ .

We know that distance is equal to speed times time.

$\text{Distance}=\text{Speed}\times\text{Time}$

Eudora ran from her home to a secret laboratory at an average speed of 12 km, so distance traveled by running would be $12x$ .

Eudora took one of her jet-packs and flew to her school at an average speed of 76 km, so distance covered by jet-packs would be $76(2-x)$ .

We are told that Eudora traveled a total distance of 120 km. We can represent this information in an equation as:

$12x+76(2-x)=120$

$12x+152-76x=120$

Combine like terms:

$-64x+152=120$

$-64x+152-152=120-152$

$-64x=-32$

Divide both sides by $-64$ :

$\frac{-64x}{-64}=\frac{-32}{-64}$

$x=0.5$

Therefore, Eudora spent 0.5 hours in running.

Upon substituting $x=0.5$ in expression for time spent in flying jet-packs, we will get:

$2-x\Rightarrow 2-0.5=1.5$

Therefore, Eudora spent 1.5 hours flying using her jet-pack.

7 0

3 years ago