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marusya05 [52]
3 years ago
14

Is all negative numbers intergers ?

Mathematics
2 answers:
miskamm [114]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

because an integer is all whole numbers and their opposites

kobusy [5.1K]3 years ago
5 0

Answer:

Yes. Intergers are all whole numbers so negative whole numbers are included too.

Step-by-step explanation:

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15x^2 + 41x + 28 <br><br>STEP BY STEP ANSWER PLSSS​
maria [59]

Answer:

(3x+4)(5x+7)

Step-by-step explanation:

15x^2 +41x+28

Factor the expression by grouping. First, the expression needs to be rewritten as 15x^2 +ax+bx+28. To find a and b, set up a system to be solved.

a+b=41

ab=15×28=420

Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 420.

1,420

2,210

3,140

4,105

5,84

6,70

7,60

10,42

12,35

14,30

15,28

20,21

Calculate the sum for each pair.

1+420=421

2+210=212

3+140=143

4+105=109

5+84=89

6+70=76

7+60=67

10+42=52

12+35=47

14+30=44

15+28=43

20+21=41

The solution is the pair that gives sum 41.

a=20

b=21

Rewrite 15x^2 +41x+28 as (15x^2 +20x)+(21x+28).

(15x^2 +20x)+(21x+28)

Factor out 5x in the first and 7 in the second group.

5x(3x+4)+7(3x+4)

Factor out common term 3x+4 by using distributive property.

(3x+4)(5x+7)

7 0
3 years ago
Read 2 more answers
How many times larger is 4 x 10^8 than 2 x 10^-5
True [87]

Answer:The answer is 8x10^7

Step-by-step explanationi took the thing

7 0
2 years ago
How many factors of 2 are there in 2³? answers&gt; 1 2 3 5​
algol [13]

Answer:

2

Step-by-step explanation:

2^3= 2*2*2

factors of 8= 1,2,4,8

factors of 2= 1,2

6 0
2 years ago
Solve the equation, if possible. (If all real numbers are solutions, enter REALS. If there is no solution, enter NO SOLUTION.) x
UkoKoshka [18]

Answer:

REALS. all real numbers are solution for the equation

Step-by-step explanation:

for the equation

x² = (x + 3)*(x − 3) + 9

distributing the terms in the parenthesis

x² = (x + 3)*(x − 3) + 9  = [x² - 3*x + 3*x - 3*3 ] + 9

x² = x² - 9 + 9

0 = 0

since this statement will be true regardless of the value of x , then the equation has solution for all real numbers .

6 0
3 years ago
A rectangular solid has width w, a length of 7 more than the width, and a height that is equivalent to 15 decreased by 3 times t
dexar [7]

Answer:

For a rectangular solid with:

width = w

length = l

height = h

The volume is equal to:

V = w*l*h

in this case we know that:

width = w.

"length of 7 more than the width"

l = w + 7.

"a height that is equivalent to 15 decreased by 3 times the width."

h = 15 - 3*w

Then the volume will be:

V = w*l*h = w*(w + 7)*(15 - 3w) = (w^2 + 7*w)*(15 - 3*w)

V =  ( -3*w^3 + 15*w^2 + 105*w - 21*w^2)

V = (-3*w^3 - 6*w^2 + 105*w)

Now, the maximum volume will be for the value of w such that:

V'(w) = 0.

and:

V''(W) < 0

Where:

dV/dw = V'(w).

dV'/dw = V''(w)

Then first we need to differentiate the equation for the volume.

V'(w) = dV/dw = ( 3*(-3*w^2) + 2*(-6*w) + 105)

V'(w) = -9*w^2 - 12*w + 105.

Then we need to find the solution for:

-9*w^2 - 12*w + 105 = 0.

We can use the Bhaskara formula, and we will get:

w = \frac{+12 +-\sqrt{(-12)^2 - 4*(-9)*105} }{2*-9}  = \frac{+12 +- 62.6}{-18}

Then the two solutions are:

w₁ = (+12 - 62.6)/(-18) = 2.81

w₂ = (+12 + 62.6)/(-18) = -15.5

But we can not have a negative width, so we can just discard the second solution.

Now let's check the second condition for the maximum, we must have:

V''(2.81) < 0.

V'' = dV'/dw = 2*(-9*w) - 12 = -18*w - 12

V''(2.81) = -18*2.81 - 12 = -62.58 < 0 .

Then the volume is maximized when w = 2.81, and the maximum volume will be:

V(2.81) =  (-3*(2.81)^3 - 6*(2.81)^2 + 105*2.81) = 180.1

 

8 0
2 years ago
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