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3 years ago

What is 30% of 70 for big ideas math

Mathematics

1 answer:

VashaNatasha [74]3 years ago

3 0

Answer:

Step-by-step explanation:

30 Percent of 70 could be written .3 × 70. .3 times 70 is 21

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Solve for x:<br><br> 2^x=17^x<br><br>

beks73 [17]

Answer:

x = 0

Step-by-step explanation:

Equation: 2ˣ = 17ˣ

For all equations like this, we will always end up with x = (a)x, a being some random number.

In that situation, that becomes (1 - a)x = 0 --> x = ⁰/₍₁ ₋ ₐ₎ --> x = 0

4 0

3 years ago

Two step equation -5=d/4+3

Karolina [17]

Answer:

If you are looking for d the answer is -32.

Step-by-step explanation:

-5=d/4+3

-3 -3

(4)-8=d/4(4)

-32 =d

8 0

3 years ago

Which number can each term of the equation be multiplied by to eliminate the fractions before solving-3/4m-1/2=2+1/4m

densk [106]

<h2>Hello!</h2>

The answer is: 4

The smallest whole number we can use to multiply each term in order to eliminate the fractions is 4:

Multiplying each side of the equation by 4, we have:

$(\frac{-3m}{4}-\frac{1}{2})*4=(2+\frac{1}{4})*4\\\\\frac{-12m}{4} - \frac{4}{2} = 8+\frac{4m}{4}\\-3m-2=8+m\\-8-2=m+3m\\4m=-10\\m=\frac{-10}{4}=\frac{-5}{2}\\\\m=\frac{-5}{2}$

Have a nice day!

8 0

3 years ago

Read 2 more answers

a rectangle has a height of n3+4n2+3n and a width of n^3+5n^2 express the area of the entire rectangle

alukav5142 [94]

<u>Given</u>:

It is given that the height of the rectangle is $n^3+4n^2+3n$

The width of the rectangle is $n^3+5n^2$

We need to determine the area of the entire rectangle.

<u>Area of the rectangle:</u>

The area of the rectangle can be determined using the formula,

$A=height \times width$

Substituting the values, we have;

$A=(n^3+4n^2+3n)(n^3+5n^2)$

Multiplying each term within the parenthesis, we get;

$A=n^{3} n^{3}+n^{3} \cdot 5 n^{2}+4 n^{2} n^{3}+4 n^{2} \cdot 5 n^{2}+3 n n^{3}+3 n \cdot 5 n^{2}$

Simplifying, we get;

$A=n^{6}+5 n^{5}+4n^{5}+20 n^{4}+3 n^{4}+15 n^{3}$

Adding the like terms, we have;

$A=n^{6}+9n^{5}+23 n^{4}+15 n^{3}$

Thus, the area of the entire rectangle is $n^{6}+9 n^{5}+23 n^{4}+15 n^{3}$

5 0

4 years ago

In circle P diameter QS measures 30 cm.

kow [346]

<u>Given</u>:

The diameter of the circle P is 30 cm.

The radius of the circle P is 15 cm.

The measure of ∠RPS is 125°

We need to determine the arc length of QR.

<u>Measure of ∠QPR:</u>

The angles QPR and RPS are linear pairs.

Thus, we have;

$\angle QPR + \angle RPS=180^{\circ}$

Substituting the values, we have;

$\angle QPR + 125^{\circ}=180^{\circ}$

$\angle QPR =55^{\circ}$

Thus, the measure of ∠QPR is 55°

<u>Arc length of QR:</u>

The arc length of QR can be determined using the formula,

$Arc \ length =(\frac{\theta}{360})2 \pi r$

Substituting $\theta=55$ and r =15, we get;

$Arc \ length =(\frac{55}{360})2 (3.14)(15)$

$Arc\ length = \frac{5181}{360}$

$Arc \ length =14.4 \ cm$

Thus, the arc length of QR is 14.4 cm.

Hence, Option d is the correct answer.

4 0

3 years ago