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2 years ago

Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)

Mathematics

1 answer:

lys-0071 [83]2 years ago

6 0

Answer:

y=-2/3x-2

Step-by-step explanation:

slope= -2/3

y=-2/3x+b

enter the given points

2=4+b

b=-2

y=-2/3x-2

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What is the slope of the line that passes through the points (2,0) and

Y_Kistochka [10]

Answer:

slope = - $\frac{1}{6}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

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If the graph of the equation y=(x+2)^2 is reflected with respect to the y-axis, what is the equation of the resulting graph?

alexandr1967 [171]

Answer:

Is important to remember that the reflection of the point (a,b) across the y-axis is the point (-a,b).

Our original equation is $y= (x+2)^2$

And after the reflection respect x we got:

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Step-by-step explanation:

Is important to remember that the reflection of the point (a,b) across the y-axis is the point (-a,b).

Our original equation is $y= (x+2)^2$

And after the reflection respect x we got:

$y= (-x+2)^2$

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2 years ago

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Sedbober [7]

The answer to this is 65.

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Then we plug that in the expression for angle a.
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2 years ago

Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)​

Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)