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Papessa [141]
3 years ago
15

Find the equation of the line perpendicular to y=3/2x-9 and passes through the point (6,2)​

Mathematics
1 answer:
lys-0071 [83]3 years ago
6 0

Answer:

y=-2/3x-2

Step-by-step explanation:

slope= -2/3

y=-2/3x+b

enter the given points

2=4+b

b=-2

y=-2/3x-2

You might be interested in
In MON, J, K, and L are midpoints. If JL = 11, LK = 13, and ON = 20, and JL || MN, LK || MO, and JK || ON, what is the length of
In-s [12.5K]

Answer:

The lengths of MN is 22 units, MO is 26 units and JK is 10 units

Step-by-step explanation:

<em>A l</em><em>ine segment</em><em> joining the </em><em>mid-points of two sides</em><em> in a triangle is </em><em>parallel to the third side</em><em> and </em><em>equal to half its length</em>

In Δ MON

∵ J, K, and L are mid-points

∵ JL // MN and LK // MO

∴ L is the mid-point of ON

∴ J is the mid-point of MO

∴ K is the mid-point of MN

∵ J, L are the mid-points of MO and ON

∵ JL is opposite to MN

→ By using the rule above

∴ JL = \frac{1}{2} MN

∵ JL = 11 units

∴ 11 = \frac{1}{2} MN

→ Multiply both sides by 2

∴ 22 = MN

∴ MN = 22 units

∵ K, L are the mid-points of MN and ON

∵ KL is opposite to MO

→ By using the rule above

∴ KL = \frac{1}{2} MO

∵ KL = 13 units

∴ 13 = \frac{1}{2} MO

→ Multiply both sides by 2

∴ 26 = MO

∴ MO = 26 units

∵ J, K are the mid-points of MO and MN

∵ JK is opposite to ON

→ By using the rule above

∴ JK = \frac{1}{2} ON

∵ ON =20 units

∴ JK = \frac{1}{2} (20)

∴ JK = 10 units

∴ The lengths of MN are 22 units, MO is 26 units and JK is 10 units

3 0
3 years ago
Write the expression in standard form. <br><br> 27ℎ ÷ 3ℎ
Andrews [41]

Answer:

I think 9h

Step-by-step explanation:

Since both variable are the same, you can divide the numbers. 27/3=9. Add back in the variable, and the answer would be 9h. That's how I would solve it at least

6 0
3 years ago
What is a scale factor?
Blababa [14]

Answer:

Here is some helpful information from my mini lessons.

Step-by-step explanation:

If two objects have the same shape, they are called "similar." When two figures are similar, the ratios of the lengths of their corresponding sides are equal. To determine if the triangles shown are similar, compare their corresponding sides. Here you'll learn that the ratio of the perimeters of similar figures is equal to their scale factor and that the ratio of their areas is equal to the square of their scale factor. If two polygons are similar, then the ratio of the lengths of any two corresponding sides is called the scale factor. This means that the ratio of all parts of a polygon is the same as the ratio of the sides.

3 0
3 years ago
Select the number and name of the terms below (select 2): 2121
mihalych1998 [28]
Its a monomial and it has 4 terms
6 0
3 years ago
Can u answer all three pls
faust18 [17]

Answer:

1. 28ft

2. 26ft

3. 20ft

Step-by-step explanation:

here ya go

5 0
3 years ago
Read 2 more answers
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