I’m tryna look for that too
Answer:
1) Event A = 2/3
Event B = 1/2
2) 1/2
Step-by-step explanation:
1)
Event A :
No. we need on dice = 4
Total numbers on dice = 6
Hence sample space of the event = 6
P( getting 4) = 4/6 = 2/3
Event B :
A coin has a head & a tail.
Hence sample space of the event = 2
But as we need tail only ,
P ( getting Tail ) = 1/2 [ if only tossed once ]
2)
Total numbers on a die = 6
Total no. of odd numbers on die = 3 (∵ 1 , 3 & 5 are odd )
Sample space of this event = 6
P (getting an odd number) = 3/6 = 1/2
Answer:
12
Step-by-step explanation:
12 dimes is $1.20, so your total for the quarters is $3.25. Since there are 25 coins total and 12 of them are dimes, 25 - 12 = 13, so you have 13 quarters. 13 times its value of 25 cents leaves you with $3.25, fulfilling your needed total.
There likely was an easier way to do this, but I'm unfamiliar with it so I ended up doing this.
9m+5=-13
9m=-18
m=-18/9
m=-2
