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3 years ago

Need help in this ASAP

Mathematics

1 answer:

Artemon [7]3 years ago

4 0

Answer:

The m∠YXW is 125°.

Addition equation: m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°

Step-by-step explanation:

To find the m∠YXW you would need to add the m∠YXZ and m∠ZXW together:

m∠YXW = m∠YXZ + m∠ZXW = 85° + 40° = 125°

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3 years ago

Does anyone know the answer?

motikmotik

Answer:

We conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

Step-by-step explanation:

From the given right-angled triangle,

Base = p+1

Perpendicular = 2p-6

Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

$=\frac{1}{2}\left(p+1\right)\left(2p-6\right)$

Factor 2p-6: 2(p-3)

$=\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}$

Divide the number: 2/2 = 1

$=\left(p+1\right)\left(p-3\right)$

$\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd$

$=pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)$

$=pp-3p+1\cdot \:p-1\cdot \:3$

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Therefore, we conclude that the area of the right triangle is:

$A\:=p^2-2p-3$

Hence, option A is correct.

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3 years ago

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4 years ago

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Step-by-step explanation:

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2 years ago

Could someone please explain how to solve for the area?

mixas84 [53]

9514 1404 393

Answer:

779.4 square units

Step-by-step explanation:

You seem to have several problems of this type, so we'll derive a formula for the area of an n-gon of radius r.

One central triangle will have a central angle of α = 360°/n. For example, a hexagon has a central angle of α = 360°/6 = 60°. The area of that central triangle is given by the formula ...

A = (1/2)r²sin(α)

Since there are n such triangles, the area of the n-gon is ...

A = (n/2)r²sin(360°/n)

For a hexagon (n=6) with radius 10√3, the area is ...

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2 years ago

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