Answer:
triangle JKL
Step-by-step explanation:
This is because the lengths of each side JKL is a factor to ABC
respectively .
AB=12,JK=36
AC=13,JL=39
BC=5,KL=25
I hope you understand
Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?
Rewrite the equation −2y=3x+7 in the form
Here the slope of the given line is
If
is the slope of perpendicular line, then

Answer 1: 
Part B. The slope of the line y=−2x+3 is -2. Since
then lines from part A are not parallel to line a.
Since
both lines are not perpendicular to line a.
Answer 2: Neither parallel nor perpendicular to line a
Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then
2·5+5·(-4)=b,
10-20=b,
b=-10.
Answer 3: 2x+5y=-10.
Part D. The slope of the line
is
Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then
7=-4·2+b,
b=7+8,
b=15.
Answer 4: y=-4x+15.
Part E. Consider vectors
These vectors are collinear, then

Answer 5: 
X^1/2 - x
-2x^3 - x^1/2 - x
-2x^3 - 2x
i think this is it
fjhdfdsfklsdfsfsdfdfdfsfs
40/50 is the ratio because the cos formula is adjacent over hypotenuse and you can reduce it to 4/5 as a fraction :)