(5-9)^2 - [5-9]
=(-4)^2 - [-4]
=(16) + 4
=20
(two negatives=positive)
Answer:
6in
Step-by-step explanation:
Midsegment thrm: half the sum if the lengths of the bases
32= 1/2(58+x)
32=29+ 1/2x
3= 1/2x
6=x
Answer:
(x + 2) is a factor of f(x)
Step-by-step explanation:
Using the remainder theorem to divide f(x) by (x - h)
Evaluate f(h) and if equal to 0 then (x - h) is a factor
f(- 3) = (- 3)³ - 7(- 3)² + 36 = - 27 - 63 + 36 ≠ 0
f(- 2) = (- 2)³ - 7(- 2)² + 36 = - 8 - 28 + 36 = 0
f(- 6) = (- 6)³ - 7(- 6)² + 36 = - 216 - 252 + 36 ≠ 0
f(2) = 2³ - 7(2)² + 36 = 8 - 28 + 36 = 16 ≠ 0
Hence (x + 2) is a factor of f(x)
Answer:
- (x - 3y)(3x + y)
Step-by-step explanation:
Given
(x + 2y)² - (2x - y)² ← expand both parenthesis using FOIL
= x² + 4xy + 4y² - (4x² - 4xy + y²) ← distribute
= x² + 4xy + 4y² - 4x² + 4xy - y² ← collect like terms
= - 3x² + 8xy + 3y² ← factor out - 1 from each term
= - 1(3x² - 8xy - 3y²) ← factor the quadratic
Consider the factors of the product of the coefficient of the x² term and the coefficient of the y² term which sum to give the coefficient of the xy- term.
product = 3 × - 3 = - 9 and sum = - 8
The factors are - 9 and + 1
Use these factors to split the xy- term
3x² - 9xy + xy - 3y² ( factor the first/second and third/fourth terms )
= 3x(x - 3y) + y(x - 3y) ← factor out (x - 3y) from each term
= (x - 3y)(3x + y)
Thus
(x + 2y)² - (2x - y)² = - (x - 3y)(3x + y)
