-8x-2y=-24
-2y=-24+8x
2y=24-8x
Y=12-4x
Y=-4x+12
Answer:
Step-by-step explanation:
The lower bound is 10.5 and the upper bound is 15.9
Hope it helps!
Answer:
16Km due east of school P
Step-by-step explanation:
Given
A school P is 16km due west of a school Q
Thus, we can say that distance PQ = 16 km.
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now we have to find the bearing of Q from P
As distance is same
distance PQ = distance QP
Thus,
Distance will remain same of 16 km.
For direction,
If Q is west of P, then P will be east of Q
as shown in figure P is west of Q,
now from point P , Q is west P.
Thus,
Bearing of School Q from P is 16Km due east of school P
Answer:
|9.4-1.8|
Step-by-step explanation:
To find distance, you take the largest value minus the smallest value and then take the absolute value of that because distance can't be negative.
Answer: x = 25
Step-by-step explanation:
If these angles are congruent, that means they are equal. Using that information, we can frame the following equation:
(x+15) = (3x-35)
To find 'x', we just need to solve the above equation.
(x+15) = (3x-35)
x+15 = 3x-35
x-3x = -35-15
-2x = -50
x = 25.
Therefore, 'x' is 25 degrees.