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Lady_Fox [76]
3 years ago
9

Which shape could not be a cross section for this cube?

Mathematics
1 answer:
insens350 [35]3 years ago
5 0
Either A hexagan or B octagan
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Rank in decreasing order 8.58, 8.508, 7.058, 7.5
8_murik_8 [283]
7.5 8.58 7.058 8.508
8 0
2 years ago
A random sample of 150 men found that 88 of the men excercise regularly, while a random sample 200 women found that 130 of the w
melamori03 [73]

Answer:

The hypothesis is:

<em>H₀</em>: p_{X}-p_{Y}=0.

<em>Hₐ</em>: p_{X}-p_{Y}.

Step-by-step explanation:

Let <em>X</em> = number of men who exercise regularly and <em>Y</em> = number of women who exercise regularly.

The information provided is:

n_{X}=150\\X=88\\n_{Y}=200\\Y=130

Compute the sample proportion of men and women who exercise regularly as follows:

\hat p_{X}=\frac{X}{n_{X}}=\frac{88}{150}=0.587

\hat p_{Y}=\frac{Y}{n_{Y}}=\frac{130}{200}=0.65

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 150 and \hat p_{X}=0.587.

The random variable <em>Y</em> also follows a Binomial distribution with parameters <em>n</em> = 200 and \hat p_{Y}=0.65.

According to the Central limit theorem, if from an unknown population large samples of sizes <em>n</em> > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

\hat p=p

The standard deviation of this sampling distribution of sample proportion is:

\sigma_{\hat p}=\sqrt{\frac{\hat p(1-\hat p)}{n}}

So, the sampling distribution of the proportion of men and women who exercise regularly follows a Normal distribution.

A two proportion <em>z</em>-test cab be performed to determine whether the proportion of women is more than men who exercise regularly.

The hypothesis for this test cab be defined as:

<em>H₀</em>: The proportion of women is same as men who exercise regularly, i.e. p_{X}-p_{Y}=0.

<em>Hₐ</em>: The proportion of women is more than men who exercise regularly, i.e. p_{X}-p_{Y}.

6 0
3 years ago
Read 2 more answers
...........answers plz
Ira Lisetskai [31]

Answer:

0

Step-by-step explanation:

m = 21, n = 12

so we just plug these into the equation

(1/3)(21) -1 -(1/2)(12)

(21/3) -1 -(12/2)

7 -1 -6

6 -6

0

3 0
2 years ago
HURRRY!!!! NO BOTS OR SPAM OR I WILL MAKE YOU PAY!!!!
const2013 [10]

Answer:

i believe its 21.5

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A dealer sells a certain type of chair and a table for $40. He also sells the same sort of table and a desk for $83 or a chair a
vesna_86 [32]
Chair=x

Table=y

Desk=z

\begin{Bmatrix}x+y&=&40\\y+z&=&83\\x+z&=&77\end{matrix}

keep the first row as normal, then in the other ones, we can isolate Y and X

\begin{Bmatrix}x+y&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

now we can replace at first row...

\begin{Bmatrix}(77-z)+(83-z)&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}160-2z&=&40\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&40-160\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}-2z&=&-120\\y&=&83-z\\x&=&77-z\end{matrix}

\begin{Bmatrix}z&=&60\\y&=&83-z\\x&=&77-z\end{matrix}

now we can replace the Z to discovery the other value

\begin{Bmatrix}z&=&60\\y&=&83-60\\x&=&77-60\end{matrix}

\boxed{\boxed{\boxed{\begin{Bmatrix}Chair&=&17\\Table&=&23\\Desk&=&60\end{matrix}}}}
6 0
3 years ago
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