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AlladinOne [14]
2 years ago
15

How many four-digit positive integers can be formed by using the digits from 1 to 9 so that two digits are equal to each other a

nd the remaining two are also equal to each other but different from the other two ?
Mathematics
1 answer:
weqwewe [10]2 years ago
6 0

Answer:

432

Step-by-step explanation:

We are given that a four digit number can be formed by using digits from 1 to 9.

Two digits equal to each other and other two digits are equal to each other .

We have to find number of four digit numbers can be formed using digits from 1 to 9.

Total digits =9

Number of ways to filled first place =9

Number of ways to filled second place =1  because two digits are same

Number of ways to fill the third place =8 because different from previous  two digits

Number of ways to fill the fourth place =1 because remaining two digits are same

Total number of ways to make four digit number =9\times 1\times 8\times 1\times {\frac{4!}{2!2!}}

Because  two digits out of 4  and  remaining two digits are same select out of 4

Total number of ways in which four digit number can be formed=9\times 8\times 3\times 2=432

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In how many ways can 4 people have different birth months?
Agata [3.3K]

Answer:

48

12 (the number of months in a year) multiplied by 4 (the number of people)

6 0
3 years ago
Someone purchase 12 books. But needs 4 books for each of the projects ar school. How many projects would they need
Fudgin [204]
3 projects.
12/4=3. Please mark me brainliest rly wanna mark up!
7 0
3 years ago
Write the equation in standard form. Identity the center and radius.<br> x² + y2 + 8x-4y-7=0
lorasvet [3.4K]

Answer:

equation;

(x + 4) {}^{2}  + (y - 2) {}^{2}  = 27

Center (-4,2)

Radius is

3 \sqrt{3}

Step-by-step explanation:

Since the x^2 and y^2 have the same coeffiecent this will be a circle in a form of

(x - h) {}^{2}  + (y - k)  {}^{2}  =  {r}^{2}

Where (h,k) is center

r is the radius

So first we group like Terms together

{x}^{2}  + 8x  +  {y}^{2}  - 4y - 7 = 0

Add 7 to both sides

{x}^{2}  + 8x +  {y}^{2}  - 4y = 7

( {x}^{2}  + 8x) +(  {y}^{2}  - 4y) = 7

Since the orginal form of the equation of the circle has a perfect square we need to complete the square for each problem

(\frac{8}{2} ) {}^{2}  = 16

and

( - \frac{4}{2} ) {}^{2}  = 4

so we have

{x}^{2}  + 8x + 16 +  {y}^{2}  - 4y + 4y = 7 + 16 + 4

{x}^{2}  + 8x + 16  +  {y}^{2}  - 4y + 4y = 27

(x + 4) {}^{2}  +  (y  - 2) {}^{2}  = 27

To find our center, h is -4 and k is 2

so the center is (-4,2)

The radius is

\sqrt{27}  = 3 \sqrt{3}

So the radius is 3 times sqr root of 3.

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20%20%5Cfrac%7B2%7D%7B15y%7D%20%20%2B%20%20%5Cfrac%7B3%7D%7B5y%20%7B%7D%5E%7B3%7D%20%7D" id="
Xelga [282]

Answer:

2y²   +   9

---------------

      15y³

Step-by-step explanation:

Start by identifying the LCD, and then change each fraction so that its denominator is the LCD.

Here the LCD is 15y³, which is evenly divisible by 15y and 5y³.

Focus now on the first fraction:  2 / (15y).  Multiplying numerator and denominator of this fraction by y² results in

y²·2          2y²

--------- → ----------

y²·15y       15y³           ←This is the correct LCD

Multiplying numerator and denominator of the second fraction by 3 results in:

   3·3            9

------------ → ---------

 3·5y³         15y³          ←This is the correct LCD

So now those two original terms look like:

 2y²         9

--------- + --------

 15y³       15y³

and this can be written in simpler form as:

2y²   +   9

---------------

      15y³

3 0
3 years ago
How many times will interest be added to the principal in 1 year if the interest is compounded annually?
Elena-2011 [213]
Hello!
Annually means once a year so if it is compounded annually then it is compounded only once per year, meaning interest is added to principal only 1 time per year.

Hope this helps! Any questions please just ask!! Thank you so much!!
7 0
2 years ago
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