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balu736 [363]
3 years ago
9

One angle of a triangle measures 136°. The other two angles are congruent. Enter and solve an equation to find the measure x of

the congruent angles. An equation is ( ) = 180. The congruent angles each measure ( )°.
Mathematics
1 answer:
Juliette [100K]3 years ago
7 0

<u>136 + x + x = 180. Or, to simplify, 136 + 2x = 180. The congruent angles measure 23 degrees each.</u>

We know this because of a simple rule that goes for all triangles: The measures of all three angles in a triangle will <em>always</em> add up to 180 degrees.

One angle of a triangle measures 136 degrees. The other two angles are congruent (have the same measure).

(x stands for an unknown angle measure.) So the equation we would use is 136 + 2x = 180. We can solve this within a few steps.

1. We subtract 136 from 2x in order to isolate 2x. But if we subtract something from the left side of the equation, we have to subtract it from the right side too. Otherwise the equation will be wrong; We would be taking away the balance.

2x = 180 - 136

2. Now that 2x is isolated, we solve 180 - 136.

2x = 46

3. If we know now that 2x is equal to 46, how do we find out what x is equal to? We divide by 2 (on both sides or it'll be wrong) to get x.

2x = 46

2x/2 = 46/2

x = 23

Now we know! x = 23... The other two angles are both 23 degrees. We can check to see if that's right by solving 23 + 23 + 136... Does it add up to 180? Yes! :)

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3 years ago
Which linear equation has no solution?
olga_2 [115]

Answer:

Option A

Step-by-step explanation:

Given:

  • a. 3x-5= 3x + 5
  • b. 3x-5= 3x - 5
  • c. 3x - 5 = 2x+5
  • d. 3x-5 = 2x + 10

To find:

  • Which one of the linear equations have no solution.

Solution:

a)  3x-5= 3x + 5

Add 5 to both sides

3x-5= 3x + 5

3x - 5 + 5 = 3x + 5 + 5

Simplify

(Add the numbers)

3x - 5 + 5 = 3x + 5 + 5

3x = 3x + 5 + 5

(Add the numbers)

3x  = 3x + 5 + 5

3x = 3x + 10

Subtract 3x from both sides

3x = 3x + 10

3x - 3x = 3x + 10 - 3

Simplify

(Combine like terms)

3x -3x = 3x + 10 - 3

0 = 3x + 10 - 3

(Combine like terms)

0 = 3x + 10 - 3

0 = 10

The input is a contradiction: it has no solutions

b)  3x-5= 3x - 5

Since both sides equal, there are infinitely many solutions.

c)  3x - 5 = 2x+5

Add 5 to both sides

3x = 2x + 5 + 5

Simplify  2x + 5 + 5 to 2x + 10

3x = 2x + 10

Subtract 2x from both sides

3x - 2x = 10

Simplify 3x - 2x to x.

x = 10

d) 3x-5 = 2x + 10

Add 5 to both sides

3x = 2x + 10 + 5

Simplify 2x + 10 + 5 to 2x + 15

3x = 2x + 15

Subtract 2x from both sides

3x - 2x = 15

Simplify 3x -2x to x.

x = 15

--------------------------------------------

Answer:

As you can see all c and d both have solutions, eliminating them as options. Option B has infinite solutions leaving Option A which has no solutions.

Therefore, <u><em>Option A</em></u> is the linear equation that has no solution.

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