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andreyandreev [35.5K]
3 years ago
9

Brenda observes that the keyboard and the screen of an open laptop lie on two different planes. In how many lines do the planes

containing the keyboard and the screen intersect ?
Mathematics
2 answers:
Citrus2011 [14]3 years ago
7 0
Answer: 1

------------------------------------------

Explanation:

The keyboard and screen can be thought of as flat rigid sheets of paper. They are joined along one single line which is where the hinge is located. Any two planes intersecting will form a single straight line assuming these planes are not parallel to one another.

jasenka [17]3 years ago
3 0

Answer: One line.

Step-by-step explanation:

We know that a plane is a two dimensional flat platform , which has infinite length and width.It contains infinite number of lines.

The intersection of two planes is a line .

Given statement : Brenda observes that the keyboard and the screen of an open laptop lie on two different planes.

Then In only one line the planes containing the keyboard and the screen intersect .

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Write the ratio 2/3 to 8 as a fraction in simplest form
Zielflug [23.3K]

Do you mean: 2/3 of 8? If yes, then we have:

 

2/3 X 8=16/3=5 1/3


8 0
3 years ago
SHOW YOUR WORK.
alexandr1967 [171]
Answer:

Explanation:

1.
f(5) = 5(5^2) - 4(5) + 1
= 125 - 20 + 1
= 106

2. (g + h)(x) = (3x - 2) + (x + 1)
= 3x - 2 + x + 1
= 4x - 1

3. f(1) - h(1) = [5(1^2) - 4(1) + 1] - [(1) + 1]
= (5 - 4 + 1) - (2)
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3 years ago
What is the shape of the cross-section formed when a plane containing line AC and line EH intersects this cube? What is the area
Aliun [14]
Given a cube of sides 4 units with vertices: A, B, C, D, E, F, G, H such that the top square is ABCD and the bottom square is EFGH with AC, BD the diagonals of the top square and EG, FH the diagonals of EFGH.

The shape of the cross-section formed when a plane containing line AC and line EH intersects the cube is the rectangle ACEH.

We obtain the value of line AC which is equal to line EH using the pythagoras rule which states that c^2=a^2+b^2, where c is the length of line AC, a is the length of line AB = 4 and b is the length of line BC = 4.

Thus, 
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Therefore, the shape of the cross-section formed when a plane containing line AC and line EH intersects the cube is the rectangle ACEH with length of 4 \sqrt{2} units and width of 4 units.

Area of a rectangle is given by
Area = length x width
=4 \sqrt{2}\times4=16 \sqrt{2} square units.
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3 years ago
What polygon has 4 equal sides, 2 obtuse angles and 2 acute angles?
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3 years ago
(4a^2 b)^4 (-a^3/2b)^2
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Answer:

64a^14b^6

Step-by-step explanation:

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4 years ago
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