All categories

3 years ago

Solve in 10 seconds or less

Mathematics

1 answer:

FromTheMoon [43]3 years ago

3 0

Answer:

1 and 7/8 is the difference between the greatest and least amounts of rainfall.

Step-by-step explanation:

You might be interested in

A can of tuna has a volume 18pi cm3 and a height of 2 cm. Find the area of the label that wraps around the entire can and does n

Sphinxa [80]

Answer:

The area of the label is $12\pi\ cm^{2}$

Step-by-step explanation:

step 1

Find the radius

we know that

The volume of the cylinder (can of tuna) is equal to

$V=\pi r^{2} h$

In this problem we have

$V=18\pi\ cm^{3}$

$h=2\ cm$

substitute and solve for r

$18\pi=\pi r^{2} (2)$

Simplify

$18=r^{2}(2)$

$r^{2}=9$

$r=3\ cm$

step 2

<em>Find the lateral area of the can</em>

The lateral area of the cylinder (can of tuna) is equal to

$LA=2\pi rh$

we have

$r=3\ cm$

$h=2\ cm$

$LA=2\pi (3)(2)=12\pi\ cm^{2}$

5 0

3 years ago

What is the ratio of the width of the yard to the area of the yard in 10 feet long by 7 feet wide

dezoksy [38]

Area = (length) x (width)

Area = (10-ft) x (7-ft) = 70 ft²

(Width) / (Area) = (7-ft) / (70 ft²) = 1 / 10-ft .

4 0

3 years ago

Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i

shepuryov [24]

Answer:D) 1 hr

Step-by-step explanation:

Given

Pump A and B can fill tank in $\frac{6}{5} hr$

Pump A and C can fill tank in $\frac{3}{2} hr$

Pump B and C can fill tank in $2 hr$

Let A be the total hr taken A therefore rate of $A=\frac{1}{A} /hr$

Let B be the total hr taken B therefore rate of $B=\frac{1}{B} /hr$

Let C be the total hr taken C therefore rate of $C=\frac{1}{C} /hr$

$\frac{1}{A}+\frac{1}{B}=\frac{5}{6}$ -----1

$\frac{1}{B}+\frac{1}{C}=\frac{1}{2}$ -----2

$\frac{1}{A}+\frac{1}{C}=\frac{2}{3}$ -----3

Adding 1,2 & 3

$2(\frac{1}{A}+\frac{1}{B}+\frac{1}{C})=\frac{5}{6}+\frac{1}{2}+\frac{2}{3}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=\frac{2}{2}$

$\frac{1}{A}+\frac{1}{B}+\frac{1}{C}=1$

thus time taken by A,B and C combined is 1 hr

7 0

2 years ago

What is the answer to log↓2(x)-3=1

sveticcg [70]

If u are trying to solve for x is that x=2

7 0

3 years ago

A professor has recorded exam grades for 10 students in his class, but one of the grades is no longer readable. If the mean sco

Nostrana [21]

Answer:

unreadable score = 35

Step-by-step explanation:

We are trying to find the score of one exam that is no longer readable, let's give that score the name "x". we can also give the addition of the rest of 9 readable s scores the letter "R".

There are two things we know, and for which we are going to create equations containing the unknowns "x", and "R":

1) The mean score of ALL exams (including the unreadable one) is 80

so the equation to represent this statement is:

mean of ALL exams = 80

By writing the mean of ALL scores (as the total of all scores added including "x") we can re-write the equation as:

$\frac{R+x}{10} =80$

since the mean is the addition of all values divided the total number of exams.

in a similar way we can write what the mean of just the readable exams is:

$\frac{R}{9} = 85\\$ (notice that this time we don't include the grade x in the addition, and we divide by 9 instead of 10 because only 9 exams are being considered for this mean.

Based on the equation above, we can find what "R" is by multiplying both sides by 9:

$\frac{R}{9} = 85\\R=85*9= 765$

Therefore we can now use this value of R in the very first equation we created, and solve for "x":

$\frac{R+x}{10} =80\\\frac{765+x}{10} =80\\765+x=80*10=800\\765+x=800\\x=800-765=35$

4 0

3 years ago