Standard form of a linear equation is Ax + By = C, where A, B, C are constants.
So,
y-8 = 3(x+1)
y-8 = 3x + 3
substract 3 from both sides,
y-8-3 = 3x+3-3
y-11 = 3x
substract y from both sides,
y-y-11 = 3x-y
-11 = 3x-y
So, the standard form is 3x-y = -11
Answer:
A_ 1,2,4,5,-1, or,-2
3 plus any of these will always leave you with a positive number of 1-8
B_ -1, -3, -4, -5, or 1
-2 plus any of these will leave you with a negative number of -7 through -1
C_ 1+(-1)
2+(-2)
3+(-3)
4+(-4)
5+(-5)
since all the numbers are 1-5 are both negative and positive these will cancel out and equal to zero.
Step-by-step explanation:
Answer:
hello your question is incomplete attached below is the complete question and solution
answer : general solution ( X ) = 
Step-by-step explanation:
attached below is the detailed solution to determine the general solution of the given system
general solution ( X ) = 
A normal space<span> is a </span>topological space X<span> that satisfies </span><span>Axiom T4</span><span>: every two disjoint </span>closed sets<span> of </span>X<span> have disjoint </span>open neighborhoods<span>.</span>
Answer:
It is given 50 paise, 25 paise and 10 paise are in the ratio 2:3:5. =4:3:2.
Step-by-step explanation:
Hope this helps