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3 years ago

Given: 3r + 2[3 (r-1) + 2] = 2(3r + 4) prove: r = 10/3

Mathematics

1 answer:

sveticcg [70]3 years ago

8 0

So I work this out on a sheet of paper and I'm pretty sure I did this right.

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Negative one-half(–4a – 6) + a2 for a = 8

stepladder [879]

Answer:

Leon multiplied 8 by 2 when he should have raised 8 to a power of 2.

The multiplication of two negative values in step 4 should result in a positive value.

The correct answer should be 83.

Step-by-step explanation:

I did it i was correct

3 0

3 years ago

Can anyone help me with 23? Thanks yall!!

kondaur [170]

See the file attached and let me know whether you understand the explanation.

8 0

3 years ago

Find the measure of A A:46 B:90 C:134 D:88

grigory [225]

Answer:

Option d = 88

Step-by-step explanation:

Angle c = 46 degrees

46 + 46 = 92

180 - 92 = 88

5 0

3 years ago

Read 2 more answers

Factorizar Sumas de cubo 1) 8x³ + 1 2) 27a³ + b³ 3) 8x³ + 1,000

frutty [35]

$\huge{\mathbb{{ANSWERS}}}$

1.) 8x³ + 1

 $\underline{ \tt{{(2x + 1) \times (4 {x}^{2} - 2x + 1)}}}$

2.) 27a³ + b³

 $\underline{ \tt{{(3a + b) \times (9{a}^{2} - 3ab + {b}^{2})}}}$

3.) 8x³ + 1,000

$\underline{ \tt{{8(x + 5) \times ( {x}^{2} - 5x + 25)}}}$

Note: My anwer is base on my knowledge

Hopefully Help:)

#CarryOnLearning

_MafiaQueen4

8 0

3 years ago

exam p A drawer contains four pairs of socks, with each pair a different color. One sock at a time is randomly drawn from the dr

Marta_Voda [28]

Answer:

The probability that the maximum number of draws is required is 0.2286

Step-by-step explanation:

The probability that the maximum number of draws happens when you pick different colors in the first four pick.

Assume you picked one sock in the first draw. Its probability is 1, since you can draw any sock.

In the second draw, 7 socks left and you can draw all but the one which is the pair of the first draw. Then the probability is $\frac{6}{7}$

In the third draw, 6 socks left and you can draw one of the two pair colors which are not drawn yet. Its probability is $\frac{4}{6}$

In the forth draw, 5 socks left and only one pair color, which is not drawn. The probability of drawing one of this pair is $\frac{2}{5}$

In the fifth draw, whatever you draw, you would have one matching pair.

The probability combined is 1× $\frac{6}{7}$ × $\frac{4}{6}$ × $\frac{2}{5}$ ≈ 0.2286

5 0

4 years ago